X = 28
u have 2 similar triangles with a scale factor of 1/7
Answer:
Step-by-step explanation:
Let the integer be 6 for even and 7 for odd (say)
For 6, we divide by 2, now get 3. Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16. Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.
The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.
Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.
Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.
Assuming yo meant
4(3b+2)²=64
divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2
A is answer
its is the same as multiplying normally .
For example 1-2-3-4-5-6-7-8- 2 times 2
you just take the starting number (2) and times it by the other number (2) and youll get 4
I can't really answer this problem if we focus only on the given information. However, I found a similar problem to this with a given diagram. This is shown in the picture attached. As you can observe, two arcs have equal measures of 65° and two have measures of 115°. Thus, the congruent arcs are:
<em>EH = HG and EF = GF.</em>
