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andrew-mc [135]
1 year ago
13

Which system is equivalent y=-2x^2 y=x-2

Mathematics
2 answers:
german1 year ago
7 0
The wording of your question suggests that there were answer choices.  Mind sharing them?

The system   <span>y=-2x^2 y=x-2 would be best written as:

</span><span>y=-2x^2 
y=x-2                  If you subst. x-2 for y in the first equation, you'll get:
                           x-2 = -2x^2,   or 2x^2 + x - 2 = 0.
                           </span>
Travka [436]1 year ago
3 0

Answer:

Step-by-step explanation:

y= -2x^{2}\\and\\y =x-2

substituting y =x-2 in equation first we get

y= -2x^{2}

(x-2)= -2x^{2}

2x^{2}+x-2=0

solving it using quadratic formula we get

x =-1.281 and corresponding y =-3.281

for x =0.781 we have y =-1.219

more over we can graph both given and find the points of intersection from it.

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You used p minutes one month on your cell phone. The next month you used 75 fewer minutes. Simplify the expression.
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Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l
slamgirl [31]

Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

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