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andrew-mc [135]
2 years ago
13

Which system is equivalent y=-2x^2 y=x-2

Mathematics
2 answers:
german2 years ago
7 0
The wording of your question suggests that there were answer choices.  Mind sharing them?

The system   <span>y=-2x^2 y=x-2 would be best written as:

</span><span>y=-2x^2 
y=x-2                  If you subst. x-2 for y in the first equation, you'll get:
                           x-2 = -2x^2,   or 2x^2 + x - 2 = 0.
                           </span>
Travka [436]2 years ago
3 0

Answer:

Step-by-step explanation:

y= -2x^{2}\\and\\y =x-2

substituting y =x-2 in equation first we get

y= -2x^{2}

(x-2)= -2x^{2}

2x^{2}+x-2=0

solving it using quadratic formula we get

x =-1.281 and corresponding y =-3.281

for x =0.781 we have y =-1.219

more over we can graph both given and find the points of intersection from it.

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What is the value of x if g^x-1-2= 25?
SVETLANKA909090 [29]

Answer:

Third option: x=\frac{5}{2}

Step-by-step explanation:

<h3> The correct exercise is attached.</h3>

The equation given is:

9^{x-1}-2=25

 The steps to find the value of "x" are shown below:

1. Add 2 to both sides of the equation:

9^{x-1}-2+2=25+2\\\\9^{x-1}=27

2. Descompose 9 and 27 into their prime factors:

9=3*3=3^2\\27=3*3*3=3^3

3. Substitute them into the equation:

3^{2(x-1)}=3^3

4. Knowing that If a^n=b^m, then n=m, we get:

2(x-1)=3

5. Apply Distributive property:

2x-2=3

6. Add 2 to both sides:

2x-2+2=3+2\\\\2x=5

7. Divide both sides of the equation by 2:

\frac{2x}{2}=\frac{5}{2}\\\\x=\frac{5}{2}

3 0
2 years ago
Read 2 more answers
The type of part being manufactured today should be 1.27 inches wide, with a tolerance of 0.04 inches. If a part does not meet t
olasank [31]
The range of widths is {1.23,1.31} so none will be rejected, answer A.

3 0
2 years ago
Read 2 more answers
A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil
Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 20 children

            r = number of success = none of the 20 children

            p = probability of success which in our case is probability that

                   children are unvaccinated, i.e; p = 13.5%

<u><em>Let X = Number of children that are unvaccinated</em></u>

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

           P(X = 0)  =  \binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}

                          =  1\times 1 \times 0.865^{20}

                          =  0.055

<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>

8 0
2 years ago
Simplify!!! <br><br>I need help please ​
satela [25.4K]

Answer:

\frac{4^{21}}{5^{6}}

Step-by-step explanation:

\frac{4^{7*3}}{5^{2*3}}=\frac{4^{21}}{5^{6}}

3 0
2 years ago
Round each weight to the nearest whole gram. Then estimate the total weight of the coins in Allen’s hand. 2.500,5.000,2.268,5.67
irina1246 [14]
So the rounded weights would be 3, 5, 2, 6, and 11, as when you round, you look at the number to the right of the one you want to round to. If it's 5 or larger, you add one to the spot you're rounding to, and make the rest of the numbers after into zeroes. If it's below 5, just change the ones after the one you want to round to into zeroes and don't add one.

Then for the estimating of the weight, you would add them together. 3+5+2+6+11. That would equal 27, so the estimate weight is 27 grams.
8 0
2 years ago
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