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Ede4ka [16]
2 years ago
10

The potential energy, P, in a spring is represented using the formula P = kx2. Lupe uses an equivalent equation, which is solved

for k, to determine the answers to her homework.
Which equation should she use?

k = 2Px2
k = Px2
k = 2p/x2
k = p/2x2
Mathematics
2 answers:
Rus_ich [418]2 years ago
7 0
K = 2p/x^2 You should use this equation.
ella [17]2 years ago
4 0

Original equation is P=kx^{2}

So, kx^{2} =P and

k=\frac{P}{x^{2} }

If we compare this equation with the given options, we can easily find that this matches with the last one k=\frac{p}{2x^{2} } with P = p/2.

Hence, correct option is k=\frac{p}{2x^{2} }.

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production for five people was as follows: 8 units, 11 units, 6 units, 12 units, 8 units. what was their average production in u
zlopas [31]
Add all the units together 8+11+6+8=45
then divide by the the number of units there are which is 5 so 45÷5 =9
4 0
2 years ago
Read 2 more answers
A ball is thrown from a height of 43 meters
AveGali [126]
When the ball will hit the ground, the height will be zero. So we need to replace h with 0 in our equation, and solve for t:
0=43-4t-5t^{2}
-5t^{2}-4t+43=0
To solve this equation we are going to use the quadratic formula: t= \frac{-b(+/-) \sqrt{b^{2}-4ac} }{2a}.
From our height equation, we can infer that a=-5, b=-4, and c=43. So lets replace those values in our quadratic formula to find t
t= \frac{-(-4)(+/-) \sqrt{(-4)^{2}-4(-5)(43)} }{2(-5)}
t=- \frac{5}{8} - \frac{ \sqrt{713} }{8} or t=- \frac{5}{8} + \frac{ \sqrt{713} }{8}
t=-3.96 or t=2.71
Since time cannot be negative, t=2.71 is the solution of our equation.

We can conclude that the ball will hit the ground after 2.71 seconds.
4 0
2 years ago
In the figure, CD = EF and AB = CE. Complete the statements to prove that AB = DF.
viva [34]

Answer:

1. Addition Property of Equality

2. Segment addition

3. Substitution Property of Equality.

4. Transitive Property of Equality.

Step-by-step explanation:

Here, given : CD = EF and AB = CE

To Show:  AB = DF

Now, as given in the steps:

1. CD + DE = EF + DE by the (addition) Property of Equality.

As we have added the EQUAL QUANTITY on both sides of the equality.

2.CE = CD + DE and DF = EF + DE by (segment addition).

As here CE and DF are line segments. And the length of  a

Line Segment = Sum of all its parts in which it is divided.

3.CE = DF by the (Addition, subtraction, substitution, transitive)Property of Equality.

Here, as  we know CE  = CD  + DE

but CD  = EF , so SUBSTITUTE EF in place of CD

⇒ CE = EF + ED  = FD (by substitution) Property of Equality.

4.Given, AB = CE and CE = DF implies AB = DF by the (transitive)Property of Equality.

As, x = y , y = z ⇒ x = z is the TRANSITIVE PROPERTY

3 0
2 years ago
Read 2 more answers
kabir spends 1/3of his pocket money on books,1/5on traveling and rest on food.if his pocket money is 450 rupees how much money d
Talja [164]

Answer:

210

Step-by-step explanation:

450 X 1/3 = 150

450 X 1/5 = 90

.

90 + 150 = 240

.

450 - 240 = 210

4 0
2 years ago
Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zarrin [17]

Correction:

Because F is not present in the statement, instead of working on​P(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0
2 years ago
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