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notka56 [123]
2 years ago
9

Suzanne owns a small business that employs 555 other people. Suzanne makes \$100{,}000$100,000dollar sign, 100, comma, 000 per y

ear, and the other 555 employees make between \$40{,}000$40,000dollar sign, 40, comma, 000 and \$50{,}000$50,000dollar sign, 50, comma, 000 per year.
Suzanne decides to increase her salary by \$30{,}000$30,000dollar sign, 30, comma, 000 per year and leave the rest of the salaries the same.
How will increasing her salary affect the mean and median? How will increasing her salary affect the mean and median?
Mathematics
2 answers:
zalisa [80]2 years ago
6 0

Answer:

16

Step-by-step explanation:

Tpy6a [65]2 years ago
6 0

Answer:

Mean increased

Median remains same

Step-by-step explanation:

Suzanne make $ 100 k per year

5 other employee  $ 40 k  to $ 50 K per year per employee

data in ascending order

$40000  , $40000+a  , $40000+b  , $40000+c   , $50000  , $ 100000

where 10000 ≥c ≥ b ≥ a ≥ 0

Mean = ($40000 + $40000+a + $40000+b  + $40000+c  + $50000 + $ 100000) /6

Mean = $(310000 + a + b + c)/ 6

Median = ($40000+b  + $40000+c )/2 =  $40000 + (b+c)/2

Suzanne make now $ 100000 + $  30000 = $ 130000 per year

$40000  , $40000+a  , $40000+b  , $40000+c   , $50000 , $ 130000

Mean = ($40000 + $40000+a + $40000+b  + $40000+c  + $50000 + $ 130000) /6

Mean = $(340000 + a + b + c)/ 6

Median = ($40+b k + $40+c k)/2 =  $40 + (b+c)/2 k

Mean increased by  $(340000 + a + b + c)/ 6 - $(310000 + a + b + c)/ 6

= $ 30000/6  = $ 5000

Median Remains the same

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Whole numbers are written on cards and then placed in a bag. Pilar selects a single card, writes down the number, and then place
tatuchka [14]

Answer:

The answer is A (i just took the test)

Step-by-step explanation:

Answer: The outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment

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The Relative Frequency: 0.05   0.35   0.26   0.13     0.21

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2 years ago
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Point Y is the midpoint of segment XZ. If XY = 2(3x +1) and YZ = 5x + 22, find the value of x.
Ede4ka [16]
<h3>Point Y is the midpoint of segment XZ. Then value of x is 20</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>Point Y is the midpoint of segment XZ</u></em>

XY = 2(3x +1)

YZ = 5x + 22

To find: Value of x

Since, Point Y is the midpoint of segment XZ,

Therefore,

XY = YZ

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6x + 2 = 5x + 22

6x - 5x = 22 - 2

<h3>x = 20</h3>

Thus, value of x is 20

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2 years ago
If triangle LMN has an obtuse angle at vertex M, which statements could be true? Check all that apply.
nirvana33 [79]

Answer: Triangle LMN is an obtuse triangle.

The angle at vertex L is acute.

The angle at vertex N is acute.

Step-by-step explanation:

Here,  triangle LMN has an obtuse angle at vertex M,

Thus, by the definition of obtuse angle triangle LMN is an obtuse triangle,

Now, Angle M is obtuse,

⇒ 90° < m∠ M < 180°

Since, by the property of a triangle,

m∠ L + m∠ M + m∠ N = 180°

⇒  m∠ M = 180° - ( m∠ L+ m∠ N )

⇒ 90° < 180° - ( m∠ L+ m∠ N ) < 180°

⇒ 90° - 180° < - ( m∠ L+ m∠ N ) < 0

⇒ -90° < - ( m∠ L+ m∠ N ) < 0

⇒ 90° >  ( m∠ L+ m∠ N ) > 0      ( Since, a < b ⇒ - a > - b)

⇒ 90° > m∠ L and 90° > m∠ N

⇒ Both angle L and angle N are acute.

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2 years ago
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A report states the average selling price is almost $520,000. Which measure of center was most likely used for the report?
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Answer:

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Step-by-step explanation:

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A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an
Amanda [17]

Answer: \mu_x=18\text{ hours}

\sigma_x=4\text{ hours}

Step-by-step explanation:

We know that mean and standard deviation of sampling distribution is given by :-

\mu_x=\mu

\sigma_x=\dfrac{\sigma}{\sqrt{n}}

, where \mu = population mean

\sigma =Population standard deviation.

n= sample size .

In the given situation, we have

\mu=18\text{ hours}

\sigma=6\text{ hours}

n= 2

Then, the expected mean and the standard deviation of the sampling distribution will be :_

\mu_x=\mu=18\text{ hours}

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Hence, the the expected mean and the standard deviation of the sampling distribution :

\mu_x=18\text{ hours}

\sigma_x=4\text{ hours}

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