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2 years ago

What is the area of a circle with a radius of 9.4cm

Mathematics

2 answers:

Contact [7]2 years ago

8 0

$A \\ = \pi r ^{2} \\ = 3.14 \times {9.4}^{2} \\ = 277.4504$

Answer : Area = 277.45cm^2

Hope this helps. - M

inessss [21]2 years ago

6 0

$\mathtt{S=\pi*r^2}\\\mathtt{=\pi*(9,4)^2}\\\mathtt{=\pi*88,36}\\\mathtt{=if \pi=3\Rightarrow\,265,08}\\\mathtt{=if \pi=3,14\Rightarrow\,277,4504\,cm^2}$

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qwelly [4]

Answer:

h = 13

Step-by-step explanation:

Given the area of a triangle as 84.5 .

The correct value to complete the formula to calculate for the height h is 13 .

Area of a triangle = 1/2 b x h

b = base

h = height

Using the above formula

84.5 = 1/2 x 13 x h

84.5 = 13/2 x h

84.5 = 6.5 x h

84.5 = 6.5h

Divide both sides by 6.5 to get h

84.5/6.5 = 6.5h /6.5

13 = h

h = 13

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2 years ago

Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ

solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.

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2 years ago

You and your friend each collect rocks and fossils. Your friend collects three times as many rocks and half as many fossils as y

pochemuha

Answer:

I collect 4 rocks and 16 fossils. While my friend collects 12 rocks and 8 fossils.

Step-by-step explanation:

The number of total objects collected by me = 20

The number of objects collected by my friend = 20

Let us assume:

The number of rocks collected by me = m

The number of fossils collected by me = 2 k

⇒ m + 2 k = 20 .... (1)

So, according to the question:

The number of rocks collected by my friend = 3 x (rocks collected by me)

= 3 x (m) = 3 m

The number of fossils collected by my friend = 1/2 x (fossils collected by me) = 1/2 x (2k ) = k

⇒ 3 m + k = 20 .... (2)

Solving (1)and (2) for the value of m and k, we get:

m + 2 k = 20 ⇒ m = 20 - 2 k ... Put this in (2)

3 m + k = 20 ⇒ 3 (20 - 2 k) + k = 20

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or, - 5k = -40

or, k = 40/5 = 8

⇒ k= 8

m + 2(8) = 20

or, m = 4

Hence, the number of rocks collected by me = m = 4

The number of fossils collected by me = 2 k = 2 (4) = 16

Hence, the number of rocks collected by my friend = 3 m = 3 x 4 = 12

The number of fossils collected by my friend = k = 8

Hence, I collect 4 rocks and 16 fossils. While my friend collects 12 rocks and 8 fossils.

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2 years ago

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Answer:

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