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padilas [110]
1 year ago
9

In this activity, you will use equations to represent this proportional relationship: Olivia is making bead bracelets for her fr

iends. She can make 3 bracelets in 15 minutes.
Part A
Find the constant of proportionality in terms of minutes per bracelet.

Part B
What does the proportionality constant represent in this situation?

Part C
Write an equation to represent the proportional relationship. Use the constant of proportionality you found in part A. Be sure to assign a variable for each quantity.

Part D
Now find the constant of proportionality in terms of number of bracelets per minute.

Part E
What does the proportionality constant represent in this situation?

Part F
Write an equation to represent the proportional relationship. Use the constant of proportionality you found in part D. Be sure to assign a variable for each quantity.

Part G
How are the constants of proportionality you found in parts A and D related?

Part H
Are the two equations you developed in parts C and F equivalent? Explain.
​​
Mathematics
1 answer:
Valentin [98]1 year ago
3 0

Answer:

Step-by-step explanation:

A) The constant of proportionality in terms of minutes per bracelet is

15/3 = 5 minutes per bracelet

B) The constant of proportionality represents man hour rate

C) let k = constant of proportionality, t = time in minutes and b = number of bracelets produced. Therefore,

t = kb

D) the constant of proportionality in terms of number of bracelets per minute is

3/15 = 1/5

E) The constant of proportionality represents production rate

F) let k = constant of proportionality, t = time in minutes and b = number of bracelets produced. Therefore,

b = kt

G) The constants of proportionality are reciprocals

H) Two equations are equivalent if they have the same solution. They are not equivalent. By inputting the different values of k, the solutions will always be the same. Therefore, they are equivalent.

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Svetach [21]

Let , side lawn is a.

Area of boundary is :

A=4\times5\times a\\\\A=20a\ m^2

Now, total cost is given by :

T=20a\times 36.25\\\\90625=725a\\\\a=125\ m

Area left is :

A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2

Price to empty space with turfs is :

P=A'\times 20\\\\P=13125\times 20\\\\P=262500

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.

Hence, this is the required solution.

3 0
1 year ago
Under ideal conditions a certain bacteria population is known to double every three hours. Suppose that there are initially 100
lara [203]

Answer:

the estimation of the size of the population after 20 hours is 10159

Step-by-step explanation:

The computation of the size of the population after 20, hours is shown below;

= 100  2^(20 by 3)

= 10159.36

If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant

3 0
1 year ago
Read 2 more answers
In how many ways can you put seven marbles in different colors into two jars? Note that the jars may be empty.
ahrayia [7]

Answer:

128

Step-by-step explanation:

You have two jars and seven marbles.

You do 2^{7}.

That is 128

3 0
1 year ago
Henry is asked to find the exact value of cos 10pi/3. His steps are shown below.
nata0808 [166]

Answer:

<em>A) The reference angle should be </em><u><em>\frac{\pi }{3},</em></u><em> and the sign of the value should be </em><u><em>negative.</em></u>

Step-by-step explanation:

cos(\frac{10\pi }{3})

Remove full rotations of 2π until the angle is between 0 and 2\pi.

cos(\frac{4\pi }{3})

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the third quadrant.

 -cos(\frac{\pi }{3})

The exact value of cos(\frac{\pi }{3}) is \frac{1}{2}.

−\frac{1}{2}    

8 0
2 years ago
Read 2 more answers
A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dim
Bingel [31]
We have the following dimensions:
w=wide
w+70=length

We have a right triangle:
leg₁=w
leg₂=w+70
hypotenuse=130

Pythagoras theorem:
leg₁²+leg₂²=hypotenuse²
Then:

w²+(w+70)²=130²

We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
(2w²+140w-12000)/2=0/2
w²+70w-6000=0

w=(-70⁺₋√(4900+24000)) / 2
=(-70⁺₋170) / 2
We have two possible solutions:
Solution 1

w=(-70-170)/2=-120   (this solution is not possible because the result is negative and it have no sense in this problem).

Solution 2

w=(-70+170)/2=50  (this is the right solution)

w=50
w+70=120

ANSWER:  the length would be 120 u  (u=units of length ) and the wide would be 50 u.
5 0
2 years ago
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