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Ulleksa [173]
2 years ago
15

If the fastest you can safely drive is 65 mi/h, what is the longest time you can stop for dinner if you must travel 569 mi in 9.

5 h total? if the fastest you can safely drive is 65 , what is the longest time you can stop for dinner if you must travel 569 in 9.5 total? 0.75 h 0.90 h 0.60 h you can't stop at all.
Mathematics
1 answer:
stellarik [79]2 years ago
4 0

Divide total miles by speed to get how long it will take to drive:

569 miles / 65 mi/h = 8.75 hours.

Now subtract the time it takes to drive from the total time you can travel:

9.5 hours - 8.75 hours = 0.75 hours.

You can stop for 0.75 hours.

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Jesse has reached 16% of his weekly reading time goal so far this week. If he has read for a total of
bekas [8.4K]
200 min
16/100=32/x
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6 0
1 year ago
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Today, John ran 15 miles in 2 hours and 30 minutes. He wants to represent the relationship between the distance he ran, in miles
jeyben [28]

Answer:

d = 6t

Step-by-step explanation:

Firstly, lets change the 2 hours and 30 minutes to 2.5 hours, you could devide the time in minutes by 60 to get that number 2[hours]+(\frac{30}{60})[minutes to hours] = 2.5Hours.

Anyway, John ran 15 miles in 2.5 hours which means he ran (15÷2.5) in one hour which is equal to 6miles per hour. That means if you multiply the hours he ran by 6 you will get the miles he ran.

So the answer would be:

d = 6t

3 0
1 year ago
Find the measure of angle x in the figure below:
Gekata [30.6K]
45+55=100 180-100=80 that makes y = 80, and vertical angles makes x=80
5 0
2 years ago
Read 2 more answers
4C. Quintin is using the three different shaped
Sauron [17]

The smallest number of tiles Quintin will need in order to tile  his floor is 20

The given parameters;

  • number of different shapes of tiles available = 3
  • number of each shape = 5
  • area of each square shape tiles, A = 2000 cm²
  • length of the floor, L = 10 m = 1000 cm
  • width of the floor, W = 6 m = 600 cm

To find:

  • the smallest number of tiles Quintin will need in order to tile his floor

Among the three different shapes available, total area of one is calculated as;

A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2

Area of the floor is calculated as;

A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2

The maximum number tiles needed (this will be possible if only one shape type is used)

maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number=  60

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

3 \times \ smallest \ number  = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20

Thus, the smallest number of tiles Quintin will need in order to tile  his floor is 20

Learn more here: brainly.com/question/13877427

3 0
2 years ago
Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did
vladimir1956 [14]

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

4 × Usha = 32

Usha = 8 i.e her number of books.

Mukat = 5×8=40.

I HOPE IT'S OK

6 0
2 years ago
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