Ask question

Ask question

All categories

1 year ago

9

If 1m = 3.3ft, how many cubic feet is the Kuroshio Sea Tank? Show your calculations!

1 answer:

Daniel [21]1 year ago

6 0

The kuroshio sea tank is 115.5 ft

You might be interested in

jonathan ran 5 days this week. the most he ran in one day was 3.5 miles. write an inequality that shows the distance jonathan co

poizon [28]

Let m represent the number of miles this guy runs in a day.
He runs every day, so the minimum number of miles has to be greater than 0.
According to the problem statement, the max number of miles is 3.5 miles or less.

Translate this into a (symbolic) inequality.

4 0

1 year ago

Simplify the square root of four over the cubed root of four. four raised to the five sixths power four raised to the one sixth

romanna [79]

Answer:

$(B)4^{1/6}$

Four raised to the one-sixth power

Step-by-step explanation:

We want to simplify: $\dfrac{\sqrt{4} }{\sqrt[3]{4} }$

First, we apply the fractional law of indices to each term.

$\text{If } a^{1/x}=\sqrt[x]{a},$ then:\\\sqrt{4}=4^{1/2}\\\sqrt[3]{4}=4^{1/3}$

We then have:

$\dfrac{\sqrt{4} }{\sqrt[3]{4} }=\dfrac{4^{1/2} }{4^{1/3} }\\$Applying the division law of indices: \dfrac{a^m }{a^n }=a^{m-n}\\\dfrac{4^{1/2} }{4^{1/3} }=4^{1/2-1/3}\\\\=4^{1/6}$

The correct option is B.

7 0

1 year ago

Sharon wants to make key chains with different colored beads. Each key chain will look the same. Sharon will use a total of 20 g

skelet666 [1.2K]

20 green and 20 red ?

8 0

1 year ago

Read 2 more answers

Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch

enot [183]

Answer:

$y=\frac{-7t^2+22t-7}{7t-22}$

Step-by-step explanation:

We are given that

Initial value problem

$y'=(t+y)^2-1$ , y(3)=4

Substitute the value $z=t+y$

When t=3 and y=4 then

z=3+4=7

$y'=z^2-1$

Differentiate z w.r.t t

Then, we get

$\frac{dz}{dt}=1+y'$

$z'=1+z^2-1=z^2$

$z^{-2}dz=dt$

Integrate on both sides

$-\frac{1}{z}dz=t+C$

$z=-\frac{1}{t+C}$

Substitute t=3 and z=7

Then, we get

$7=-\frac{1}{3+C}$

$21+7C=-1$

$7C=-1-21=-22$

$C=-\frac{22}{7}$

Substitute the value of C then we get

$z=-\frac{1}{t-\frac{22}{7}}$

$z=\frac{-7}{7t-22}$

$y=z-t$

$y=\frac{-7}{7t-22}-t$

$y=\frac{-7-7t^2+22t}{7t-22}$

$y=\frac{-7t^2+22t-7}{7t-22}$

8 0

2 years ago

Sue had finished three Christmas gifts before the first of December. After that she finished one gift each day. Which equation d

Verdich [7]

Xxxxxxxxxxxxxxxxxxxx

6 0

1 year ago