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Lerok [7]
2 years ago
9

If 1m = 3.3ft, how many cubic feet is the Kuroshio Sea Tank? Show your calculations!

Mathematics
1 answer:
Daniel [21]2 years ago
6 0
The kuroshio sea tank is 115.5 ft
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Solve: the quantity 3x minus 15 divided by 2 = 4x
Anon25 [30]

Answer:

x=-3

Step-by-step explanation:

(3x-15)/2 = 4x

Multiply each side by 2

(3x-15)/2 *2= 4x*2

3x-15 = 8x

Subtract 3x from each side

3x-15-3x = 8x-3x

-15 = 5x

Divide each side by 5

-15/5 = 5x/5

-3 =x

5 0
2 years ago
A scatter plot containing the point (6, 8) has the regression equation yˆ=6x+4 . What is the residual e when x = 6?
Anna11 [10]

Residual is the difference between the y value of scatter plot and y value of regression equation

A scatter plot containing the point (6, 8), the y value of scatter plot is 8

y=6x+4, to get y value of regression equation we plug in 6 for x

y = 6(6) + 4 = 40

Residual e = y value of scatter plot - y value of regression equation

=8 - 40 = -32

Answer : e=-32




5 0
2 years ago
Read 2 more answers
Each month, Kaisorn deposits $50.00 onto her public transportation card. It costs her $2.50 per trip to ride the subway. Thom de
Lemur [1.5K]
The answer is the first one. Hope this helps!
8 0
2 years ago
Read 2 more answers
11. The probability that a dessert sold at a certain cafe contains chocolate is 75%. The probability that a dessert containing c
raketka [301]
probability that a dessert sold at a certain cafe contains chocolate is 86%.

The probability that a dessert containing chocolate also contains nuts is 30%.

Find the probability that a dessert chosen at random contains nuts given that it contains chocolate

P(nuts given chocolate) = .30/.86 = .349 or 34
6 0
2 years ago
At an intersection, the red-light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25
denpristay [2]

Percent of red lights last between 2.5 and 3.5 minutes is 95.44% .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that 2.5<X<3.5 is equal to the blue area under the curve.

Step 2:

Since μ=3 and σ=0.25 we have:

P ( 2.5 < X < 3.5 ) =P ( 2.5−3 <  X−μ < 3.5−3 )

⇒ P ( (2.5−3)/0.25 < (X−μ)/σ < (3.5−3)/0.25)

Since, Z = (x−μ)/σ , (2.5−3)/0.25 = −2 and (3.5−3)/0.25 = 2 we have:

P ( 2.5<X<3.5 )=P ( −2<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( −2<Z<2 )=0.9544

Percent of red lights last between 2.5 and 3.5 minutes is 0.9544(100) = 95.44% .

3 0
2 years ago
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