Brand X cost: $4.50
Brand Y cost: $3.50

Christopher spends total: $49.50

Equation: 4.50x + 3.50y = 49.50

Idk how to solve the equation but this should be the correct equation

4 0

1 year ago

5 equally sized boxes of cake mix fell off the back of Jake's truck. Together they weigh 925.98 pounds. How much does each ball

uysha [10]

we are given

5 equally sized boxes of cake mix fell off the back of Jake's truck

it means that

total number of balls =5

Together they weigh 925.98 pounds

total weighs =925.98 pounds

each ball weighs = (total weights)/(total number of balls)

now, we can plug values

each ball weighs = $\frac{925.98}{5}$

each ball weighs is 185.196 pounds..................Answer

4 0

1 year ago

Each airline passenger and his or her luggage must be checked to determine whether he or she is carrying weapons on to the airpl

Dafna1 [17]

Answer:

$P_k = 0.83$

$N_{\mu} \approx 4 \ passengers$

$T_{\lambda} = 0.5 \ minutes$

Step-by-step explanation:

From the question we are told that

The average number of passengers that arrive per minute is $\lambda = 10$

The average number of check that can be carried out in one minute is $\mu= 12$

Generally the probability that a passenger will have to wait before being checked for weapons is mathematically represented as

$P_k = \frac{\lambda }{ \mu }$

=> $P_k = \frac{10 }{ 12}$

=> $P_k = 0.83$

Generally the number of passengers are waiting in line to enter the checkpoint is mathematically represented as

$N_{\mu} = \frac{\lambda^2}{\mu (\mu -\lambda) }$

=> $N_{\mu} = \frac{10^2}{12 (12 -10) }$

=> $N_{\mu} \approx 4 \ passengers$

Generally the average time a passenger spend at the checkpoint is mathematically represented as

$T_{\lambda} = \frac{ \frac{\lambda}{(\mu - \lambda)} }{ \lambda}$

=> $T_{\lambda} = \frac{ \frac{ 10}{(12 - 10)} }{10}$

=> $T_{\lambda} = 0.5 \ minutes$

5 0

1 year ago