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S_A_V [24]
1 year ago
15

the area of a rectangle banquet hall is 7400 square feet. the length of one side of the hall is 82 feet. explain how you can use

compatable numbers to estimate the width of the hall
Mathematics
1 answer:
Vadim26 [7]1 year ago
5 0
We are given that the hall has a rectangular shape.
Area of rectangle can be calculated using the following rule:
Area of rectangle = length * width

We are also given that:
Area = 7400 square feet
length = 82 feet

Substitute with the givens in the above equation to get the width as follows:
Area of rectangle = length * width
7400 = 82 * width
width = 7400 / 82
width = 90.24390244 feet
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Mrs. Anderson surveyed her class and asked each student, "How many hours do you spend
jonny [76]

Answer:

Step-by-step explanation:

8 0
2 years ago
A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Find the lengths of the median o
nexus9112 [7]

Answer:

5/2units\\.

\sqrt{47/2}units \\.

\sqrt{41/2}units\\.

Step-by-step explanation:

The given points are A(1,2,3), B(-2,0,5) and C(4,1,5). The triangle is represented in the attach file where the three possible median are length AE, BF, and CD. We determine the coordinate of point D,E and F using the midpoint equation which is for any point A(x,y,z) and point B(a,b,c), the midpoint D is determine by

D=(\frac{x+a}{2},\frac{y+b}{2},\frac{z+c}{2})\\.

Hence going by the above formula we determine the coordinate of point D,E and F

D=(\frac{-2+1}{2},\frac{0+2}{2},\frac{5+3}{2})\\.

D=(\frac{-1}{2},1,4)\\.

point E

E=(\frac{4-2}{2},\frac{1+0}{2},\frac{5+5}{2})\\.

E=(1,\frac{1}{2},5)\\.

Point F

F=(\frac{4+1}{2},\frac{1+2}{2},\frac{5+3}{2})\\.

F=(\frac{5}{2},\frac{3}{2},4)\\.

To determine the length of each median line we use the formula for distance between two points which is express as

AB=\sqrt{(y_{2}-y_{1} )^{2} +(x_{2}-x_{1} )^{2}+(z_{2}-z_{1} )^{2}} \\.

Using the above formula we determine the length of line AE,BF and CD.

AE=\sqrt{(1-1 )^{2} +(1/2-2)^{2}+(5-3 )^{2}} \\.

AE=\sqrt{0 +9/4+4} \\.

AE=\sqrt{25/4} \\.

AE=5/2units\\.

For point BF

BF=\sqrt{(5/2+2 )^{2} +(3/2-0)^{2}+(4-5 )^{2}}\\.

BF=\sqrt{81/4 +9/4+1} \\.

BF=\sqrt{47/2} \\.

BF=\sqrt{47/2}units \\.

For point CD

CD=\sqrt{(-1/2-4 )^{2} +(1-1)^{2}+(4-5 )^{2}}\\.

BF=\sqrt{81/4 +0+1} \\.

BF=\sqrt{41/2} \\.

BF=\sqrt{41/2}units\\.

7 0
2 years ago
The diagram shows 3 identical circles inside a rectangle.
Leya [2.2K]

one side is 12 as the radius is 2 so x 2 for diameter which is 4. there are 3 circles so times it by 3 which = 12.

the other side is 4 as one circle daimeter is 4.

4 x 12 = 48.

I am not exactly sure how to do the second part but i hope this helps u

3 0
1 year ago
Roger wants to have 400 copies of his resume printed. His local print shop charges $21.50 for the first 200 copies and $10 for e
podryga [215]

Answer:

$43.99

Step-by-step explanation:

400 copies = 200 copies + 100 copies + 100 copies

Price:

200 copies - $21.50

100 additional copies - $10

100 additional copies - $10

Total = $21.50+$10+$10=$41.50

Sales tax = 6%

Find 6% of $41.50:

\$41.50\cdot 0.06=\$2.49

So, Roger will pay

\$41.50+\$2.49=\$43.99

5 0
2 years ago
A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado l
solniwko [45]

Question:

The question is incomplete. The display technology was not given. Find below the complete question and the answers.

Display from technology:

Hypothesis Test Results

μ : Mean of variable      

H₀ : μ=2.7 miles

HA  : μ >2.7 miles

Variable     Sample Mean      Std. Err.        DF           T-Stat            P-value

Length            3.23601        0.285185      499        2.230166        0.0131

Step-by-step explanation:

From the result obtained, we have;

Null hypothesis:   H₀ : μ=2.7 miles

Alternative hypothesis:   HA  : μ >2.7 miles

Test statistics = 2.230166

P-value =  0.0131

Significant level: α = 0.05

Since the P value is less than the significance level, we can reject the null hypothesis.

There is no sufficient evidence to support the claim that the mean tornado length is greater than 2.7 miles

3 0
2 years ago
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