Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:
So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B25%7D%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
Answer:
A and D
Step-by-step explanation:
Here, we shall be evaluating the validity of the statements;
A. Yes, A is true
There are four even numbers 2,4,6 and 8 and 4 odd number 1,3,5,7; The landing should be equal at 125 each
B. This is wrong
It is supposed to land half of the number of time s which is half of 250 and that is 125
C.This is wrong
The numbers greater than 4 are 5,6,7,8
Now, the probability should be 4/8 = 1/2 and that is 50%
D. This is correct
Number of times we have a landing on odd numbers is 250-135 = 115
The experimental probability of landing on an odd number is thus 115/250 = 0.46 which is 46%
Answer:
Step-by-step explanation:
hello :
100+(n-2)² = 149
100-100+(n-2)² = 149-100
(n-2)² = 49
(n-2)² - 49 =0 but 49=7²
(n-2)² - 7² =0 use identity : a²-b²=(a-b)(a+b)
(n-2-7)(n-2+7)=0
(n-9)(n+5)=0
n-9=0 or n+5=0
n=9 or n=-5
Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as
where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
is the required r
The volume of a cylinder can be found using the formula:
π r² h,
where r is the radius of the circular base and h is the height of the cylinder.
If we plug in the measurements of the cylinder, we get:
π (6²) (28)
When this is simplified, we get that the volume of the cylinder is:
1008π cubic cm
Thus, if each marble has a volume of 36π cubic cm, then to find how many marbles will fit into the vase we must divide the vases total volume by the volume of each marble.
1008π / 36π = 28
Therefore, the answer is D. 28 marbles
