Suppose a company did $3,000,000 in annual maintenance in 2013 and expects 85% of those to renew for 2014. Suppose that product
1 answer:
Answer:
In year 2013 annual maintenance done = $ 3,000,000
Out of this 85% is expected to renew in 2014 = = $2,550,000
Now Sales in 2013 = $3,000,000
60% of these sales = = $1,800,000
Now out of this 60%, 20% annual maintenance was expected to be paid
In 2014 = = $360000
So, Total annual maintenance in 2014 =
= $2,910,000
You might be interested in
Answer:
Maximum number of long sleeved shirt that can be purchase is, 8
and
Minimum number of long sleeved shirt that can be purchased is, 0
Step-by-step explanation:
let y represents the number of short sleeves and x represents the number of long sleeves.
As per the given condition:
Members of a school club are buying matching shirts. They know at least 25 members will get a shirt.
we have;
or
....[1]
Since, long sleeves shirt are $ 10 each and short sleeves shirt are $ 5 each.
then;
Total cost of long sleeves is 10x and
the total cost of short sleeves is 5y
Also; the club can spend no more than $ 165
then;
or
......[2]
Solving the inequality equation with the graph :
Plot equation [1] and [2]; we get the maximum at point (8 , 17)
so, x= 8.
If we take minimum value of x =0 then y is between 25 and 33.
so, the solution area is between the lines to the left of where the lines intersect.
Therefore, the maximum number of long sleeved shirts can be purchased is 8 and the minimum number of long sleeved shirt can be purchased is 0
