Answer:
Step-by-step explanation:
n + q = 20
.05n + .25q = 3.00
5n + 25q = 300
n + q = 20
5n + 25q = 300
-5n - 5q = -100
20q = 200
q = 10 quarters
n + 10 = 20
n = 10 nickels
(10 nickels, 10 quarters)
This is something you'll need a T table for, or a calculator that can compute critical T values. Either way, we have n = 10 as our sample size, so df = n-1 = 10-1 = 9 is the degrees of freedom.
If you use a table, look at the row that starts with df = 9. Then look at the column that is labeled "95% confidence"
I show an example below of what I mean.
In that diagram, the row and column mentioned intersect at 2.262 (which is approximate). This value then rounds to 2.26
<h3>
Answer: 2.26</h3>
Answer:
99% Confidence interval: (0.185,0.375)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 150
Number of cars that have faulty catalytic converters, x = 42
99% Confidence interval:
Putting the values, we get:
The 99% confidence interval for the true proportion of new cars with faulty catalytic converters is (0.185,0.375)
1/10 of 2000 is 200 pounds. so 200 pounds of cheese
i guess you mean 100 times more lettuce than beef so that would be 200,000 pounds of lettuce
200+200,000=200,200 final answer