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katen-ka-za [31]
2 years ago
10

At Moby’s Movies grand opening, every 8th customer will receive a free drink and every 10th customer will receive a free movie r

ental.
What number customer will be the first to receive both free gifts?
Mathematics
1 answer:
ivanzaharov [21]2 years ago
5 0
Yes that is the answer you need
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Elodia [21]

There is 179 hours left.

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2 years ago
A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

Thus; the  steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

t ≅ 153.51  minutes

4 0
1 year ago
A student walks 1/4 Mile from her home to the store on her way to a friend's house at the store is one third of the wave to her
Setler [38]
Her friend's house is 1/12 miles away from her house.

Since 1/4 miles is 1/3 of the way, 1/4 x 1/3 = 1/12.
4 0
1 year ago
Read 2 more answers
A- 5.57<br> B- 41<br> C-12<br> D-21.71
Kryger [21]

Answer:

Step-by-step explanation:

If KM bisects angle NKL, the angle 3 is congruent to angle 4.  

We are given that angle 1 is congruent to angle 2, so that means that angle JKP is congruent to angle PKN.  By the definition of an angle bisector, we know then that angle NKM is congruent to angle MKL.  By the definition of a straight angle formed by opposite rays, all those angles named above add up to equal 180 degrees.  So if angle JKN = 8x + 2 and angle MKL = 3x + 5 and angles NKM and MKL are congruent, then angle NKL = 2(3x + 5) which is 6x + 10.  Again, if all those angles above add up to equal 180, then

8x + 2 + 6x + 10 = 180 and

14x + 12 = 180 and

14x = 168 so

x = 12.

Angle MKN = 3x + 5 so if x = 12, then

Angle MKN = 3(12) + 5 and

Angle MKN = 41 degrees

4 0
1 year ago
If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes to make a yo-yo, how many hours would it take them
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If every 5 mins, A makes 1 yo-yo every 10 mins, B makes 1 yo-yo then every 10 mins, both machines produce 3 yo-yos every 10 mins (2 from machine A and 1 from machine B) Therefore, for 20 yo-yos, both machines would take 70 minutes( 1 hour and 10 mins). After 70 minutes, 21 yo-yos would be produced.
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2 years ago
Read 2 more answers
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