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2 years ago

Which equation is y=6x^2+12-10 rewritten in vertex form

Mathematics

1 answer:

Andre45 [30]2 years ago

7 0

The formula in order to obtain the vertex form of a quadratic equation is given as

y=a(x-h)^2+k where (h,k) is the vertex of the quadratic equation which is parabolic in shape and it is opening upward.

As given in the problem, y=6x^2+12x-10

Using the formula, we can transformed the quadratic equation y=6x^2+12x-10 into its vertex form:

y=6x^2+12x-10

y= (6x^2+12x)-10 (grouping)

y=6(x^2+2x)-10 (factoring Common terms per group)

y=6(x^2+2x+1)-10-6 (Completing the squares)

y=6(x+1)^2-16 (Factor and Simplify)

Hence, the vertex form of y=6x^2+12x-10 is y=6(x+1)^2-16

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2 years ago

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Option C:

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2 years ago

Cindy owns a rectangular lot that is 18 yards long and 45 feet wide. She is going to cover the lot with square pieces of sod. If

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2 years ago

Read 2 more answers

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Murljashka [212]

Answer:

Under 99% confidence level we can say that mean speed of the new chips is greater than that of the old chips

Step-by-step explanation:

$H_{0}$ : Mean speed of the new chip is the same as the old chip

$H_{a}$ : Mean speed of the new chip is greater than the old chip

to calculate the z-statistic we can use the formula:

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2 years ago

- In the following diagram of triangle QRS, QR = 8 and QS = 17. Determine the value of sin Q. Show how you

dimaraw [331]

Answer:

$SinQ=\frac{15}{17}$

Step-by-step explanation:

We draw the right triangle as shown in the image attached.

Δ QRS

Where R is the right angle

Given

QR = 8

QS = 17

Now, using Pythagorean Theorem, we can find RS:

$QR^2+RS^2=QS^2\\8^2+RS^2=17^2\\RS^2=17^2-8^2\\RS^2=225\\RS=\sqrt{225}\\RS=15$

Now, we know the ratio Sine as:

$Sin(\theta)=\frac{Opposite}{Hyotenuse}$

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So,

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This is the value of SinQ.

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2 years ago