<span><u><em>First way:</em></u>
The easiest and simplest way is to <u>count by 1</u> starting from 82 till you reach 512.
<u>This will go as follows:</u>
82, 83, 84, 85, ........... , 510, 511, 512
<u><em>Second way:</em></u>
We can note that the two given numbers are even numbers. This means that the two numbers are divisible by 2.
Therefore, we can <u>count by 2</u> starting from 82 till we reach 512.
<u>This will go as follows:</u>
82, 84, 86, 88, ................... , 508, 510, 512
<u><em>Third way:</em></u>
We can note that the units digit in both numbers is the same (the digit is 2). This means that we can count from 82 till 512 by <u>adding 10 each time</u>.
<u>This will go as follows:</u>
82, 92, 102, 112, ......................, 492, 502, 512
Hope this helps :)</span>
Devin borrowed $1,058 at 13 percent for nine months.
We have to calculate the interest paid.
Interest = 
Substituting the values of
Principal = $1058
Rate = 13%
Time = 9 months = 
year
Interest = 
Interest = 103.155
= 103.16
So, Devin will pay 103.16 as the interest.
Therefore, Option A is the correct answer.
I agree with the given answer because of the gain or loss on retirement of bonds = book value of bonds - the amount paid to the bondholders
Most likely, polygon <span>ABCD</span> has sides of known lengths.
It is also likely that one of the sides of polygon <span>EFGH</span> (not <span>EH</span>) is also known. For instance, its side <span>EF</span>.
If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
<span>r=<span><span>EF</span><span>AB</span></span></span>
Since this ratio is constant for any two corresponding lengths,
<span>r=<span><span>EH</span><span>AD</span></span></span>
From the last two equations we can derive:
<span>EH=AD⋅<span><span>EF</span><span>AB</span></span></span>
Hope That Helped : ) (Took a minute)
She scored better with math
