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ValentinkaMS [17]
2 years ago
7

mazy is loooking for his bow and discovers that has 20 shirts for every 2 pair of bows. if his has 50 shirts, how many pairs f b

ows does he have?
Mathematics
2 answers:
I am Lyosha [343]2 years ago
8 0
He has 5 bows. Add one set of 2bows and 20 shirts and add them untill you reach 40. (4 bows, 40 shirts) Then, to make 50 you add 10 so divide 20 by 2 and then 2/2 and you get 1 bow and 10 shirts. Add all that together and you get 5 bows and 50 shirts.
vlada-n [284]2 years ago
6 0
I don't quite know what you wrote but if it's 2 bows for every shirt the answer will be 100. If it is says 2 bows for every 20 shirts then the answer will be 5 bows
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The aquarium has 10 more red fish than blue fish. 60 percent of the fish are red. How many blue fish are in the aquarium?
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Answer:

20 blue fish

Step-by-step explanation:

Number of blue fish = x

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Red fish = 60% of total = 0.6

Total fish = x+x+10 = 2x+10

0.6 = (x+10)/(2x+10)

Solve for x:

1.2x+6 = x+10

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6-column table with 5 rows. The 1st column is labeled + x squared with entries +x, +x, +x, +x, +x. The 2nd column is labeled +x
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According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg
Sati [7]

Answer:

a) Mean blood pressure for people in China.

b) 38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c) 71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d) 8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e) Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg

f) 157.44mmHg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is two standard deviations from the mean or more, it is considered unusual.

In this question:

\mu = 128, \sigma = 23

a.) State the random variable.

Mean blood pressure for people in China.

b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.

This is 1 subtracted by the pvalue of Z when X = 135.

Z = \frac{X - \mu}{\sigma}

Z = \frac{135 - 128}{23}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.

This is the pvalue of Z when X = 141.

Z = \frac{X - \mu}{\sigma}

Z = \frac{141 - 128}{23}

Z = 0.565

Z = 0.565 has a pvalue of 0.7140

71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d.)Find the probability that a person in China has blood pressure between 120 and 125 mmHg.

This is the pvalue of Z when X = 125 subtracted by the pvalue of Z when X = 120. So

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 128}{23}

Z = -0.13

Z = -0.13 has a pvalue of 0.4483

X = 120

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 128}{23}

Z = -0.35

Z = -0.35 has a pvalue of 0.3632

0.4483 - 0.3632 = 0.0851

8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not?

From b), when X = 135, Z = 0.3

Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg.

f.) What blood pressure do 90% of all people in China have less than?

This is the 90th percentile, which is X when Z has a pvalue of 0.28. So X when Z = 1.28. Then

X = 120

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 128}{23}

X - 128 = 1.28*23

X = 157.44

So

157.44mmHg

6 0
2 years ago
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