Answer:
g(x)=15/20 x^2
Step-by-step explanation:
write 15/20 as a fraction then x^2 comes after it
I took the khan test and aced it
Answer:
She should buy the monthly plan for the unlimited movies rather than pay $2.99 per movie. This is because, the more she pay that amount for each movie, the higher her expenses would become at the end of each month.
For example, let assume, in a month, she 8 free days (Saturday and Sunday). She paying for each movie each of those days would supersede the amount she could have spent assuming she did the unlimited monthly plan of $7.99.
That notwithstanding other days which will feel like watching movies or the public holidays which she would be free to relax.
Step-by-step explanation:
(a) 0.059582148 probability of exactly 3 defective out of 20
(b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.
(a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So
0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)
= 0.05^3 * 0.95^17 * 20! / (3!17!)
= 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)
= 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)
= 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)
= 0.05^3 * 0.95^17 * 20*19*3
= 0.000125* 0.418120335 * 1140
= 0.059582148
(b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.
The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)
= 0.05*0.95^3*24/(1!3!)
= 0.05*0.857375*24/6
= 0.171475
So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.
Answer:
(1/2, 5)
Step-by-step explanation:
8x + 7y = 39
-2(4x - 14y = -68)
-8x + 28y = 136
8x + 7y = 39
add the two equations together
35y = 175
y = 5
8x + 7(5) = 39
8x = 4
x = 1/2
We can set up a proportion.
88% = 0.88
44/0.88 = x/1
Cross multiply:
0.88x = 44
Divide 0.88 to both sides:
x = 50
So your cell phone can hold 50 messages.
