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Alenkinab [10]
1 year ago
15

Subtract 1.05 from a certain number. Multiply the difference by 0.8, add 2.84 to the product then divide the sum by 0.01 and get

700. What is the number?
Mathematics
2 answers:
bazaltina [42]1 year ago
8 0
Answer:
The number is 6.25

Explanation:
Assume that the number we are looking for is x

First, we will set up the equations as follows:
1- Subtract 1.05 from the number (assume the result is y):
x - 1.05 = y

2- Multiply the difference by 0.8 (assume the product is z):
0.8(y) = z

3- add 2.84 to the product (assume the result is w):
z + 2.84 = w

4- divide the sum by 0.01, the quotient is 700:
w / 0.01 = 700

Now, we will work backwards as follows:
4) w / 0.01 = 700
    w = 0.01 * 700
    w = 7

3) z + 2.84 = w
    z + 2.84 = 7
    z = 7 - 2.84
    z = 4.16

2) 0.8y = z
    0.8y = 4.16
    y = 4.16 / 0.8
    y = 5.2

1) x - 1.05 = y
    x - 1.05 = 5.2
    x = 5.2 + 1.05
    x = 6.25

Hope this helps :)
Goryan [66]1 year ago
7 0
For the answer to the question above, the answer is 6.25

Here's the solution for this,
<u>{(x-1.05).08}+2.84   </u>=   700
         .01

<u>0.8x-0.84+2.84  </u>   =   700
       .01

<u>0.8x + 2 </u>                =   700
   .01

0.8x + 2                =700 x 0.01

0.8x  = 7 - 2

<u>0.8x</u>  =  <u>5
0.8</u>      .08<u>

The answer would be 6.25
</u>
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If trapezoid JKLM with vertices) (3, 4), K (6,4), L (8, 1) and M (1,1) is rotated 270 degrees counterclockwise, what are the
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Answer:

J' = (4,-3)

Step-by-step explanation:

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Required

Determine the new coordinate of J

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Last year, 46% of business owners gave a holiday gift to their employees. A survey of business owners indicated that 35% plan to
DiKsa [7]

Answer:

a) Number = 60 *0.35=21

b) Since is a left tailed test the p value would be:  

p_v =P(Z  

c) If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% the proportion of business owners providing holiday gifts had decreased from the 2008 level.  

We can use as smallest significance level 0.044 and we got the same conclusion.  

Step-by-step explanation:

Data given and notation  

n=60 represent the random sample taken

X represent the business owners plan to provide a holiday gift to their employees

\hat p=0.35 estimated proportion of business owners plan to provide a holiday gift to their employees

p_o=0.46 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Part a

On this case w ejust need to multiply the value of th sample size by the proportion given like this:

Number = 60 *0.35=21

2) Part b

We need to conduct a hypothesis in order to test the claim that the proportion of business owners providing holiday gifts had decreased from the 2008 level:  

Null hypothesis:p\geq 0.46  

Alternative hypothesis:p < 0.46  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.35 -0.46}{\sqrt{\frac{0.46(1-0.46)}{60}}}=-1.710  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

Part c

If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% the proportion of business owners providing holiday gifts had decreased from the 2008 level.  

We can use as smallest significance level 0.044 and we got the same conclusion.  

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