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Gwar [14]
2 years ago
13

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th

e distance she rides is represented by the variable d. Which statements are true of the scenario? Check all that apply.
*The independent variable, the input, is the variable d, representing distance.
*The distance traveled depends on the amount of time Marlene rides her bike.
*The initial value of the scenario is 16 miles per hour.
*The equation t = d + 16 represents the scenario.
*The function f(t) = 16t represents the scenario.

Mathematics
2 answers:
White raven [17]2 years ago
8 0

Let

t--------> the time in hours

d-------> the distance in miles

we know that

d=16t

this is a linear equation that represent the scenario

in this equation the independent variable is the time t and the dependent variable is the distance d

The distance's equation in function notation is equal to

f(t)=16t

Using a graph tool

see the attached figure

The domain of the function is the interval----------> [0,∞)

t\geq0

The range of the function is the interval------->  [0,∞)

f(t)\geq0

<u>Statements</u>

<u>a) The independent variable, the input, is the variable d, representing distance</u>

The statement is false

Because the  independent variable is the variable t

<u>b) The distance traveled depends on the amount of time Marlene rides her bike</u>

The statement is true

Because the distance's equation in function notation is equal to

f(t)=16t

<u>c) The initial value of the scenario is 16 miles per hour</u>

The statement is false

Because 16 represent the rate or  the slope of the linear equation

<u>d) The equation t = d + 16 represents the scenario</u>

The statement is false

Because, the scenario is represented by the function f(t)=16t

<u>e) The function f(t) = 16t represents the scenario</u>

The statement is true

kotegsom [21]2 years ago
7 0

Answer:

the correct answer is

b and e

just took the test.

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Two con terminal angles 3pi/4 negative and positive answer in radians
son4ous [18]

Answer:

Negative Coterminal: -5π/4

Positive Coterminal: 11π/4

Step-by-step explanation:

The easiest way to find <em>specific </em>(not infinite) coterminal values is to ±2π. When you subtract 2π, you will get a negative coterminal. When you add 2π, you will get a positive coterminal. Keep in mind though that a tan∅ or cot∅ only needs ±π, not ±2π.

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Prove that x is a subset of y then x union z is a subset of y union z for all sets x y and z
Ganezh [65]

We are to show that if X ⊆ Y then (X ∪ Z) ⊆ (Y ∪ Z) for sets X, Y, Z.

Assume that a is a representative element of X, that is, a ∈ X. By the definition of union, a ∈ X ∪ Z. Now because X ⊆ Y and we assumed a ∈ X, then a ∈ Y by the definition of subset. And because a ∈ Y, then a ∈ Y ∪ Z by definition of union.

We chose our representative element, a, and showed that a ∈ X ∪ Y implies that a ∈ Y ∪ Z and this completes the proof.

4 0
2 years ago
In a large population, 61 % of the people have been vaccinated. if 4 people are randomly selected, what is the probability that
muminat
In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.

For only one person, we use P(1), same reasoning should hold for other subscripts.

P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841

Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
8 0
2 years ago
A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
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