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2 years ago

Mention the commutativity associative and distributive properties of rational number

Mathematics

1 answer:

evablogger [386]2 years ago

6 0

Answer:

Associative property: a + (b + c), a – (b – c) ≠ (a – b) – c, a × (b × c) = (a × b) × c, and a ÷ (b ÷ c) ≠ (a ÷ b) ÷ c

When a = ½ and b = ¾

Now, for checking a × b = b × a, consider LHS and RHS.

LHS = a × b = ½ × ¾ = ⅜

RHS = b × a = ¾ × ½ = ⅜

Thus, LHS = RHS (Hence proved)

Step-by-step explanation:

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Roger is building a storage shed with wood blocks that are in the shape of cubic prisms. Can he build a shed that is twice as hi

Fynjy0 [20]

Given that Roger is building a storage shed with wood blocks that are in the shape of cubic prisms.

cube is basicallye a box which is made of squares. That is all the sides (lenght, width and height) are equal.

Now we have to determine, Can he build a shed that is twice as high as it is wide.

that means if width is 1 then height should be twice which is 2.

yes that is possible if we put one cubical prism over another cubical prism. then height of shed due to two prism will be twice than the width.

Hence correct choice should be "A. Yes. For every block of width, he could build two blocks high."

3 0

2 years ago

Read 2 more answers

Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,

seropon [69]

Answer and Step-by-step explanation:

Data provided in the question

Mean = 1.1 hours per call =

R = Mean rate = 1.6 per eight hour day

$\mu$ = $\frac{8}{1.6}$ = 5 per day

Based on the above information

a. The average number of customers is

$= \frac{R^2}{\mu(\mu- R)}$

$= \frac{1.6^2}{5(5- 1.6)}$

= 151

b. The system utilization is

$= \frac{R}{\mu}$

= $\frac{1.6}{5}$

= 0.32

c. The amount of time required is

= 1 - system utilization

= 1 - 0.32

= 0.68

And, there is 8 hours per day

So, it would be

= $0.68 \times 8$

= 5.44 hours

d. Now the probability of two or more customers is

$= 1 - (0.68 + 0.68 \times 0.32)$

= 0.1024

Therefore we simply applied the above formulas

4 0

2 years ago

Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when

valentina_108 [34]

Solution:

$f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$

We have to find the remainder when f(x) is divided by $x^2-1.$

x²-1=0

x= $\pm1$

$f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13$

So, remainder is 13 and -13.

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2 years ago

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A city distributes vehicle identification stickers using a combination of letters followed by a combination of digits, each of

gayaneshka [121]

A) 672750
B) 68250
C) 2960100

Explanation
A) We have 26 letters from which to choose 4, and 10 digits from which to choose 2:
$_{26}C_4\times_{10}C_2=\frac{26!}{4!22!}\times\frac{10!}{2!8!}=14950\times45=672750$

B) We have 26 letters from which to choose 2, and 10 digits from which to choose 4:
$_{26}C_2\times_{10}C_4=\frac{26!}{2!24!}\times\frac{10!}{4!6!}=325\times210=68250$

C) We have 26 letters from which to choose 5, and 10 digits from which to choose 2:
$_{26}C_5\times_{10}C_2=\frac{26!}{5!21!}\times\frac{10!}{2!8!}=65780\times45=2960100$

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2 years ago

The area of the rectangle is 64.8 square centimeters. What is the perimeter of the rectangle? One group of ten tenths and one gr

9966 [12]

Answer:

(a) $Perimeter = 32.2\ cm$