A. The number of 10-boards Peter bought is equal to n divided by 10. Then, each of the 10-boxes will get two boxes of nails. The number of boxes of nails that Peter will have after buying n boards will be,
N = (2)(n/10)
Simplifying,
<em> N = n/5</em>
b. If the number of boards are 90 then,
N2 = (90/10)(2)(100 nails/box)
N2 = 1800
Answer: 1800
The school can buy fifteen notebooks and nineteen tablets. 15X7=105 and 5X19=95. 95+105=200. The first thing you want to do is realize that 5Xanything will give you an answer that has a 0 or a five at the end, so you want to find a product by 7 that ends with a 0 or 5 too.
Answer:
A= Length x Width
A= 27 x (1/3 x 27 + 4)
A=27 x (9 + 4)
A= 27 x 13
A= 351
Step-by-step explanation:
ye
Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.
Answer:
Step-by-step explanation:
By applying <em>Pythagoras theorem</em> we can find hypotenuse of a right angle triangle.
Side of right angle triangle (a) = 5√2 cm
Side of right angle triangle (b) = 5√2 cm
Hypotenuse² = a² × b²
