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Stels [109]
1 year ago
11

A direct variation function contains the points (-9, -3) and (-12,4). Which equation represents the function?

Mathematics
1 answer:
Triss [41]1 year ago
3 0

Answer:

y = -\frac{7x}{3} - 24

Step-by-step explanation:

We can model this function using the equation of a line:

y = ax + b

Where a is the slope of the line and b is the y-intercept.

To find the values of a and b, we can use the two points given:

(-9, -3):

-3 = a * (-9) + b

-9a + b = -3

(-12, 4):

4 = a * (-12) + b

-12a + b = 4

If we subtract the second equation from the first one, we have:

-12a + b - (-9a + b) = 4 - (-3)

-12a + 9a = 4 + 3

-3a = 7

a = -7/3

Then, finding the value of b, we have:

-12a + b = 4

28 + b = 4

b = -24

So the equation is:

y = -\frac{7x}{3} - 24

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<em><u>The intervals included in solution are:</u></em>

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<em><u>Solution:</u></em>

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<em><u>We have to solve the inequality</u></em>

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\mathrm{Subtract\:}\frac{2}{24}\mathrm{\:from\:both\:sides}\\\\\frac{2}{x}-10-\frac{2}{24}\ge \frac{2}{24}-\frac{2}{24}\\\\Simplify\\\\\frac{2}{x}-10-\frac{2}{24}\ge \:0

\frac{2}{x}-\frac{10}{1}-\frac{2}{24} \geq 0\\\\\frac{ 2 \times 24}{x \times 24} -\frac{10 \times 24}{1 \times 24} - \frac{2 \times x }{24 \times x}\geq 0\\\\\frac{48}{24x}-\frac{240x}{24x}-\frac{2x}{24x}\geq 0\\\\Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions\\\\\frac{48-240x-2x}{24x}\geq 0\\\\Add\:similar\:elements\\\\\frac{48-242x}{24x}\ge \:0

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When we multiply or divide both sides by negative number, then we must flip the inequality sign

\frac{\left(-2\left(121x-24\right)\right)\left(-1\right)}{x}\le \:0\cdot \left(-1\right)\\\\\frac{2\left(121x-24\right)}{x}\le \:0\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{\frac{2\left(121x-24\right)}{x}}{2}\le \frac{0}{2}\\\\Simplify\\\\\frac{121x-24}{x}\le \:0

\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{121x-24}{x}\\

This is attached as figure below

From the attached table,

\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0\\\\0

<em><u>Therefore, solution set is given as</u></em>:

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

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Please find the attachment for visual understanding.

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