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2 years ago

Given: m EH =85°, m∠EYV=35°. Find: m EV .

Mathematics

1 answer:

avanturin [10]2 years ago

5 0

Answer:

155°

Step-by-step explanation:

∠EYV is half the difference of arcs EV and EH

(1/2)(EV -EH) = ∠EYV

(1/2)(EV -85°) = 35° . . . . fill in the given values

EV -85° = 70° . . . . . . . . .multiply by 2

EV = 155° . . . . . . . . . . . . add 85°

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100/225 square feet of your bakery will be used as your storefront, where customers come visit. The rest kill be used for storag

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The answer is 5/9. I showed a bit more work on the other post

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2 years ago

Ben swims 50,000 yards per week in his practices. Given this amount of training, he will swim the 100-yard butterfly in 51.5

Elanso [62]

Answer:

MArginal productivity: $\frac{dt}{dL}=-0.0002$

We can interpret this as he will reduce his time an additional 0.0002 seconds for every additional yard he trains.

Step-by-step explanation:

The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.

In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.

The marginal productivity can be expressed as:

$\frac{dt}{dL}$

where dt is the variation in time and dL is the variation in training yards.

We can not derive the function because it is not defined, but we can approximate with the last two points given:

$\frac{dt}{dL}\approx\frac{\Delta t}{\Delta L} =\frac{t_2-t_1}{L_2-L_1}=\frac{44.6-46.4}{70,000-60,000}=\frac{-2.0}{10,000}=-0.0002$

Then we can interpret this as he will reduce his time an additional 0.0002 seconds for every additional yard he trains.

This is an approximation that is valid in the interval of 60,000 to 70,000 yards of training.

6 0

1 year ago

Simplify the following expression into the form a + bi, where a and b are rational numbers.

vagabundo [1.1K]

The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
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Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
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Since we know that i = -1,
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-10i-8-6-2
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2 years ago

Read 2 more answers

The histogram to the right represents the weights (in pounds) of members of a certain high-school programming team. What is th

AVprozaik [17]

Answer:

Class width=20

Lower class limit of first class=100

Upper class limit of first class=120

Step-by-step explanation:

The class width can be calculated by taking the difference of two consecutive upper class limits or lower class limits.

Now we take any two consecutive upper class limits or lower class limits from classes 100-120,120-140,140-160,160-180,180-200,200-220,220-240.

We take upper class limits of first and second class i.e. 100 and 120.

Class width=120-100=20

Class width=20

The approximate lower and upper class limits of the first class from classes 100-120,120-140,140-160,160-180,180-200,200-220,220-240 are 100 and 120.

Class limits for first class is 100-120.

Lower class limit of first class=100

Upper class limit of first class=120

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1 year ago

How do you solve this? Please help me (i will give you 14 points)

azamat

Answer:

X can be 2,3,4,5,6,7,8

Step-by-step explanation:

X is greater than or equal to 2 and less than or equal to 8

It can only be integers

X can be 2,3,4,5,6,7,8

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2 years ago