Sarah invested $2,500 in an account paying an interest rate of 2.1% compounded continuously. Assuming no deposits or withdrawals
1 answer:
Answer:
<h2>$3,000</h2>Step-by-step explanation:
This problem is based on compound interest, and the expression for the compound interest is given as
Given Data
A = final amount = ?
P = initial principal balance = $2,500
r = interest rate = 2.1%= 0.021
t = number of time periods elapsed= 14 years
Substituting our data into the compound interest formula we can solve for the final amount
<em>Hence to the nearest hundred we have the account balance has $3,000</em>
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer