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drek231 [11]
2 years ago
7

Sarah invested $2,500 in an account paying an interest rate of 2.1% compounded continuously. Assuming no deposits or withdrawals

are made, how much money, to the nearest hundred dollars, would be in the account after 14 years?
Mathematics
1 answer:
givi [52]2 years ago
6 0

Answer:

<h2>$3,000</h2>

Step-by-step explanation:

This problem is based on compound interest, and the expression for the compound interest is given as

Given Data

A = final amount  =  ?

P = initial principal balance  = $2,500

r = interest rate = 2.1%= 0.021

t = number of time periods elapsed= 14 years

Substituting our data into the compound interest formula we can solve for the final amount

A= 2500(1+0.021)^1^4\\A= 2500(1.021)^1^4\\A= 2500*1.3377\\A= 3344.25\\

<em>Hence to the nearest hundred we have the account balance has $3,000</em>

<em></em>

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What is the value of x if g^x-1-2= 25?
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Answer:

Third option: x=\frac{5}{2}

Step-by-step explanation:

<h3> The correct exercise is attached.</h3>

The equation given is:

9^{x-1}-2=25

 The steps to find the value of "x" are shown below:

1. Add 2 to both sides of the equation:

9^{x-1}-2+2=25+2\\\\9^{x-1}=27

2. Descompose 9 and 27 into their prime factors:

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3. Substitute them into the equation:

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5. Apply Distributive property:

2x-2=3

6. Add 2 to both sides:

2x-2+2=3+2\\\\2x=5

7. Divide both sides of the equation by 2:

\frac{2x}{2}=\frac{5}{2}\\\\x=\frac{5}{2}

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