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Luden [163]
2 years ago
10

The graph represents the feasible region for the system:

Mathematics
2 answers:
seraphim [82]2 years ago
4 0
<span>it occurs when x= 15 and y= 30,</span> minimum value is 975
morpeh [17]2 years ago
3 0

We have been given a system of inequalities and an objective function.

The inequalities are given as:

y\leq 2x\\&#10;x+y\leq 45\\&#10;x\leq 30\\

And the objective function is given as:

P=25x+20y

In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.

The graph of the region is shown below:

From the graph, we can see that corner points of the feasible region are:

(x,y) = (15,30),(30,15) and (30,60).

Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.

\text{At (15,30)}\Leftrightarrow P=25\cdot 15+20\cdot 30=975\\&#10;\text{At (30,15)}\Leftrightarrow P=25\cdot 30+20\cdot 15=1050\\&#10;\text{At (30,60)}\Leftrightarrow P=25\cdot 30+20\cdot 60=1950\\

Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30

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Answer:

The 98% confidence interval would be given by (0.326;0.354)

Step-by-step explanation:

1) Notation and definitions

X=63 number of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

n=6138 random sample taken

\hat p=0.34 estimated proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

p true population proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 98% of confidence, our significance level would be given by \alpha=1-0.98=0.02 and \alpha/2 =0.01. And the critical value would be given by:

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If we replace the values obtained we got:

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0.34 + 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.354

The 98% confidence interval would be given by (0.326;0.354)

8 0
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