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2 years ago

11

Louden County Wildlife Conservancy counts butterflies each year. Data over the last three years regarding four types of butterfl

ies are shown below. What inference can be made about the butterflies in Louden County from the samples?

1 answer:

MrRa [10]2 years ago

5 0

Incomple question. However, here's the remaining part of the question:

14

2009

Meadow Fritillary= 5

Variegated Fritillary= 7

Zebra Swallowtail= 33

Eastern-Tailed Blue= 242

Louden County Butterfly Count

2010

Meadow Fritillary 34

Variegated Fritillary 95

Zebra Swallowtail 21

Eastern-Tailed Blue 168

2011

Meadow Fritillary

Variegated Fritillary

Zebra Swallowtail

Eastern-Tailed Blue

10

170

<u>Options</u>:

A) All butterfly populations are steadily decreasing.

B)All butterfly populations were larger than usual in 2010.

C)The Eastern-Tailed Blue butterfly is more common than the others.

D)The Meadow Fritillary is equally common as the Variegated Fritillary

Answer:

<u>C</u>

Step-by-step explanation:

Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.

Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.

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1. COST Mr. Rivera wants to purchase a riding lawn

antiseptic1488 [7]

Answer:

p(x) = 0.85x

t(x) = 1.065x

(t o p)(x) = 0.9x

$2700

Step-by-step explanation:

If the marked price is $x, then the function p(x) that gives the price of the riding lawn mower after 15% discount will be

$p(x) = x(1 - \frac{15}{100}) = 0.85x$

where x is the marked price.

Now, the function that gives the total cost with sales tax will be given by

$t(x) = x(1 + \frac{6.5}{100}) = 1.065x$

where x is the discounted price.

Therefore, the composite function that gives the total cost of the riding lawn mower on sale is given by

(t o p)(x) = 1.065(0.85x) = 0.9x ............ (1)

where x is the marked price.

If the marked price x = $3000, then Mr. Rivera has to pay for the riding lawn mower, from equation (1),

(t o p)(3000) = 0.9 × 3000 = 2700 dollars. (Answer)

8 0

2 years ago

In a production process, the diameter measures of manufactured o-ring gaskets are known to be normally distributed with a mean d

Art [367]

Answer:

DIRECT WAY EXCEL

"=NORM.DIST(75,80,3,TRUE)"

And we got: $P(X\leq 75)= 0.04779$

OTHER WAY

$P(X\leq 75)=P(\frac{X-\mu}{\sigma}\leq \frac{75-\mu}{\sigma})=P(Z\leq \frac{75-80}{3})=P(Z$

And we can find this probability using the normal standard table or excel:

$P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the diameter of a population, and for this case we know the distribution for X is given by:

$X \sim N(80,3)$

Where $\mu=80$ and $\sigma=3$

And we know that if the diameter is 75 or less the ring would be considered defective , so then in order to find the proportion of defective we need to find the following probability:

$P(X\leq 75)$

One way to do this in excel is with the following formula:

"=NORM.DIST(75,80,3,TRUE)"

And we got: $P(X\leq 75)= 0.04779$

And the other way is use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X\leq 75)=P(\frac{X-\mu}{\sigma}\leq \frac{75-\mu}{\sigma})=P(Z\leq \frac{75-80}{3})=P(Z$

And we can find this probability using the normal standard table or excel:

$P(Z$

3 0

2 years ago

4. Given directed line segment CD, if point E divides CD three-fourths of the way from C to D, find the coordinates of E, then p

cricket20 [7]

Answer:

Point E is given by $\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Step-by-step explanation:

Let points C and D be $(x_0,y_0),\,(x_1,y_1)$ and let point E divides it in ratio $m:n$ .

Then coordinates of point E are given by $\left ( \frac{mx_1+nx_0}{m+n},\frac{my_1+ny_0}{m+n} \right )$

Put $m:n=3:4$

Point E is given by $\left ( \frac{3mx_1+4x_0}{3+4},\frac{3y_1+4y_0}{3+4} \right )=\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Now plot point E.

3 0

2 years ago

What values of b satisfy 4(3b + 2)2 = 64?

rodikova [14]

Assuming yo meant
4(3b+2)²=64

divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2

A is answer

7 0

2 years ago

Read 2 more answers

A sociologist wishes to see if it is true that for a certain group of professional women, the average age at which they have the

Vadim26 [7]

Answer:

$Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o$

Step-by-step explanation:

The explanation of given question is described below:

Here, the test of hypothesis states that

$H_o : Mean = 28.6$

$H_a : Mean\ which\ is\ not\ equals\ 28.6$

The test statistic is

$Z = \frac{(\bar X - Mean)}{\frac{Population\ standard\ deviation}{vn} }$

$Z = \frac{(30.06 - 28.6)}{\frac{4.18}{6} }$

= 2.1

According to the given data α = 0.05,

So, the major value is

$IZ(0.025)I = 1.96$

(refer to the standard normal table) .

Finally

$Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o$

3 0

2 years ago