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Afina-wow [57]
1 year ago
6

Solve: the quantity 3x minus 15 divided by 2 = 4x

Mathematics
1 answer:
Anon25 [30]1 year ago
5 0

Answer:

x=-3

Step-by-step explanation:

(3x-15)/2 = 4x

Multiply each side by 2

(3x-15)/2 *2= 4x*2

3x-15 = 8x

Subtract 3x from each side

3x-15-3x = 8x-3x

-15 = 5x

Divide each side by 5

-15/5 = 5x/5

-3 =x

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The minimum length L of a highway sag curve can be computed by where θ 1 is the downhill grade in degrees (θ 1 < 0°), θ 2 is
8_murik_8 [283]

Answer:

The answer to the nearest foot is = 15 feet

Step-by-step explanation:

Solution

The first set taken is to  Compute L for a 55-mph speed limit

Given that

L =(θ2 -θ1)/200 (h +S Tan ∝) =

= ( u + 5) 336²/200 (1.9 +336 tan 0.7°)

= 9° (336)²/200 (1.9 +336 tan 0.7°) = 14.7652094

= 15 feet  { 9° = 9*π/180 = π/20}

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5 0
1 year ago
Which values are the result of cubing a rational number? Check all that apply
Illusion [34]
3^3 = 3 * 3 * 3 = 27
4^3 = 4 * 4 * 4 = 64
5^3 = 5 * 5 * 5 = 125
6^3 = 6 * 6 * 6 = 216
5 0
2 years ago
Read 2 more answers
A furniture store is having a sale on sofas and you're going to buy one. The advertisers know that buyers get to the store and t
KATRIN_1 [288]

Answer:

300

Step-by-step explanation:

5 0
1 year ago
Let P2 be the vector space of all polynomials of degree 2 or less, and let H be the subspace spanned by 10x2+4xâ1, 3xâ4x2+3, and
lord [1]

I suppose

H=\mathrm{span}\{10x^2+4x-1,3x-4x^2+3,5x^2+x-1\}

The vectors that span H form a basis for P_2 if they are (1) linearly independent and (2) any vector in P_2 can be expressed as a linear combination of those vectors (i.e. they span P_2).

  • Independence:

Compute the Wronskian determinant:

\begin{vmatrix}10x^2+4x-1&3x-4x^2+3&5x^2+x-1\\20x+4&3-8x&10x+1\\20&-8&10\end{vmatrix}=-6\neq0

The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of H is 3.

  • Span:

Write an arbitrary vector in P_2 as ax^2+bx+c. Then the given vectors span P_2 if there is always a choice of scalars k_1,k_2,k_3 such that

k_1(10x^2+4x-1)+k_2(3x-4x^2+3)+k_3(5x^2+x-1)=ax^2+bx+c

which is equivalent to the system

\begin{bmatrix}10&-4&5\\4&3&1\\-1&3&-1\end{bmatrix}\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}a\\b\\c\end{bmatrix}

The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives

\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}-\dfrac{6a-11b+19c}3\\\dfrac{3a-5b+2c}3\\\dfrac{15a-26b+46c}3\end{bmatrix}

so the vectors do span P_2.

The vectors comprising H form a basis for it because they are linearly independent.

4 0
2 years ago
A group of 5 friends decides to share the cost of a party together. If the party costs $1,100, how much does each friend pay?
seraphim [82]

Answer:

1,100 dollars divided by 5 friends is 220 dollars so each friend would have to pay 220 dollars

Step-by-step explanation:


7 0
1 year ago
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