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2 years ago

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A restaurant manager can spend at most $600 a day for operating costs and payroll. It costs $100 each day to operate the bank an

d $50 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at most:
50x + 100 ≤ 600

x ≤ 10
x ≥ 10
x ≥ 12
x ≤ 12

1 answer:

navik [9.2K]2 years ago

6 0

Option A

The restaurant Manager can afford at most 10 employees for the day

<em><u>Solution:</u></em>

Given that restaurant manager can spend at most $600 a day for operating costs and payroll

It costs $100 each day to operate the bank and $50 dollars a day for each employee

The given inequality is:

$50x + 100\leq 600$

Where , "x" is the number of employees per day

Let us solve the inequality for "x"

$50x + 100\leq 600$

Add -100 on both sides of inequality

$50x + 100 - 100\leq 600 - 100\\\\50x\leq 500$

Divide by 50 on both sides of inequality

$\frac{50x}{50}\leq \frac{500}{50}\\\\x\leq 10$

Hence the restaurant Manager can afford at most 10 employees for the day

Thus option A is correct

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