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Ksju [112]
2 years ago
6

22.Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls. If he wants to make all the plates identicalwitho

ut any food left over.A)What is the greatestnumber of plates Lenin can prepare?B)How many pieces of chicken and rolls will there be in eachplate?
Mathematics
1 answer:
Nitella [24]2 years ago
7 0

Answer: The greatest number of plates Lenin can prepare = 4

and there will be 3 chickens and 4 rolls in each plate.

Step-by-step explanation:

Given: Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls.

To make all the plates identical without any food left over, the greatest number of plates Lenin can prepare = G.C.D.(12,16)=4

The number of pieces of chicken in each plate = \dfrac{12}{4}=3

The number of pieces of rolls in each plate = \dfrac{16}{4}=4

So,  the greatest number of plates Lenin can prepare = 4

and there will be 3 chickens and 4 rolls in each plate.

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The following are questions from a self-quiz.According to some study, the height for Northern European adult males is normally d
lara [203]

Answer:

a) 0.064

b) 0.109

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 181 centimeter

Standard Deviation, σ = 7.3 centimeter

We are given that the distribution of height for Northern European adult males is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(person is between 160 and 170 centimeters)

P(160 \leq x \leq 170) = P(\displaystyle\frac{160 - 181}{7.3} \leq z \leq \displaystyle\frac{170-181}{7.3}) = P(-2.8767 \leq z \leq -1.506)\\\\= P(z \leq -1.506) - P(z < -2.8767)\\= 0.066 -0.002 = 0.064 = 6.4\%

b) P(person is higher than 190 centimeter)

P(x > 190)

P( x > 190) = P( z > \displaystyle\frac{190 - 181}{7.3}) = P(z > 1.2328)

= 1 - P(z \leq 1.2328)

Calculation the value from standard normal z table, we have,  

P(x > 190) = 1 - 0.891 = 0.109 = 10.9\%

7 0
2 years ago
A company produces metal slabs for industrial use. the slabs come in 3 thicknesses: 5in, 10in, and 15in. the weights of each thi
Len [333]

Given slabs thicknesses 5in, 10in, and 15in.

Therefore,<u> </u><u>ratio of thicknesses in simplest form would be 1:2:3.</u>

Metal 1 thicknesses =  150lbs, 300lbs, 600lbs

Dividing by 150, we get ratio of Metal 1 thicknesses = 1:2:4.

Metal 2 thicknesses = 130lbs, 260lbs, 390lbs.

Dividing by 130, we get ratio of Metal 2 thicknesses =  1:2:3.

Metal 3 thicknesses = 310lbs, 620lbs, 930lbs.

Dividing by 310, we get ratio of Metal 3 thicknesses = 1:2:3.

Metal 4 thicknesses = 140lbs, 280lbs, 420lbs.

Dividing by 140, we get ratio of Metal 4 thicknesses = 1:2:3.

<u>We can see the ratios of thicknesses of Metal 1 are 1:2:4 but it should be 1:2:3.</u>

Therefore, Metal 1 weight is not proportional to thickness.


5 0
2 years ago
Read 2 more answers
A football coach needs to divide 48 players into two groups. He wants the ratio of the players in group 1 to players in group 2
sergiy2304 [10]

Answer:

Step-by-step explanation: 344

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2 years ago
Pablo and Nadia are playing a game on a coordinate grid. Pablo puts a playing piece at point (-2, 3) and Nadia puts a playing pi
7nadin3 [17]

Answer:

The distance between the two playing pieces is of 6.4 units.

Step-by-step explanation:

Suppose we have two points:

A = (x_{1}, y_{1})

B = (x_{2}, y_{2})

The distance between these points is:

D = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

Distance between:

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The distance between the two playing pieces is of 6.4 units.

5 0
2 years ago
Use the values on the number line to find the sampling error.
pantera1 [17]
Part 1:

Given a number line with the point \bar{x}=3.8 and the point \mu=4.27

The sampling error is given by:

\bar{x}-\mu=3.8-4.27=-0.47



Part 2:

Given a number line with the point \bar{x}=26.43 and the point \mu=24.67

The sampling error is given by:

\bar{x}-\mu=26.43-24.67=1.76
4 0
2 years ago
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