Answer:
a. 
μ = $24.57
μ ≠ $24.57
b. 0.12
c. we fail to reject the null hypothesis since p ≈0.12 > 0.05
d. we fail to reject the null hypothesis since z ≈-1.6 > -1.96
Step-by-step explanation:
a)
μ = $24.57
μ ≠ $24.57
b)
To compute p value, we need to calculate z-score of $23.89 per hour. in the distribution assumed under null hypothesis
z-score can be calculated as follows:
where
- X= $23.89
- M is the mean value under null hypothesis ( $24.57)
- s is the sample standard deviation ($2.40)
- N is the sample size (30)
Putting the numbers in the formula we get
≈ −1,5518
The corresponding p-value is <em>two tailed </em>and ≈ 0.12
c)
since p ≈0.12 > 0.05 <em>we fail to reject the null hypothesis.</em>
d)
Critical value for the 0.05 significance level in two tailed test is :
c(z)=-1.96 Since z≈ −1,6 >-1.96, it is not in the critcal region, therefore <em>we fail to reject the null hypothesis. </em>
Hello there.
<span>
If p and q are nonzero integers, which pair of points must lie in the same quadrant?
</span>
<span>B. (p, q) and (2p, 2q)
</span>
Answer:
Check the explanation
Step-by-step explanation:
Kindly check the attached images below to see the step by step explanation to the question above.
Answer:
He ate 
of the original pizza for dinner
Step-by-step explanation:
- Lucas divides his pizza into three equal pieces for himself and his two
friends
∵ There are 1 pizza
∵ It is divided into 3 equal parts
∴ Each part is 
∴ Teddy takes of the pizza
- Teddy eats 
of his piece for lunch and a further 
of what
remains for dinner
∵ His piece is
∵ He eats of his piece for lunch
∴ He eats for lunch = × = 
- Let us find the remaining of his piece for dinner
∵ The remaining = -
- Make L.C.M for the denominators
∵ The L.C.M of 3 and 24 is 24
∵ = 
= 
∴ The remaining = -
∴ The remaining = 
= 
∵ He ate of the remaining for dinner
∵ The remaining of his piece =
∴ He ate for dinner ⇒ ×
∴ He ate for dinner ⇒ 
=
* He ate of the original pizza for dinner
Answer:
72
Step-by-step explanation:
We are assuming that all girls in the group bought the same number of items.
Therefore, we need to find the highest common factor of 72, 144 and 216.
HCF
72 = 2 * 2 * 2 * 3 * 3
144 = 2 * 2 * 2 * 2 * 3 * 3
216 = 2 * 2 * 2 * 3 * 3 * 3
The product of the emboldened numbers is the highest common factor.
That is:
2 * 2 * 2 * 3 * 3 = 72
Therefore, the largest possible number of girls in the group is 72.
