Let x represent number of redwood trees and y represent number of spruce trees.
We have been given that a park ranger bought 12 trees. We can represent this information in an equation as:
We are also told that redwood trees cost $24 each, so cost of x redwood trees would be 
.
Each spruce tree costs $16, so cost of y spruce trees would be 
.
Since the park ranger spent $208 on trees, so we can represent this information in an equation as:
Upon substituting equation (1) in equation (2), we will get:
Therefore, the park ranger bought 2 redwood trees.
Upon substituting in equation (1), we will get:
Therefore, the park ranger bought 10 spruce trees.
T= total
<span>Money spent is: </span>
48+ 1/3 (T-48) = 1/2 T
One equation for one unknown, solve:
48 + 1/3 T -1/3*48= 1/2 T
48 - 16 =1/2 T- 1/3 T
32= 1/6 T
T= 6*32
<span>T=192
</span>192-48=144 money left after watch
1/3*144=48 third of leftover, spent on pen
<span>144-48=96 left which is half of 192. </span>
base 16y^2
height y^2 + y + 3
V = b*h
V = 16y^2(y^2 + y + 3)
V = 16y^4 + 16y^3 + 48y^2
Last option
Answer:
Step-by-step explanation:
The basic model for this growth is the exponential function: y = a(b)^c, where a is the initial value, b is the growth rate and c is the time.
Here we have P = fish population = (2 fish)(3)^t
