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1 year ago

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Last Sunday 1,675 people visited the amusement park. 56% of the visitors were adults, 16% were teenagers, and 28% were children

ages 12 and under. Find the number of adults, teenagers, and children that visited the park. *

2 answers:

wel1 year ago

7 0

56Step-by-step explanation 3x12=36 36+20=56

Ierofanga [76]1 year ago

4 0

Answer:

56

Step-by-step explanation:

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Suppose babies born in a large hospital have a mean weight of 4095 grams, and a standard deviation of 569 grams. If 130 babies a

Butoxors [25]

Answer:

$P =0.3998$

Step-by-step explanation:

Let ${\overline{x}}$ be the average of the sample, and the population mean will be $\mu$

We know that:

$\mu = 4095$ gr

Let $\sigma$ be the standard deviation and n the sample size, then we know that the standard error of the sample is:

$E=\frac{\sigma}{\sqrt{n}}$

Where

$\sigma=569$

$n=130$

In this case we are looking for:

$P(|{\displaystyle{\overline{x}}}- \mu|>42)$

This is:

${\displaystyle{\overline{x}}}- \mu>42$ or ${\displaystyle{\overline{x}}}- \mu$

$P=P({\displaystyle{\overline{x}}}- \mu>42)+ P({\displaystyle{\overline{x}}}- \mu$

Now we get the z score

$Z=\frac{{\displaystyle{\overline{x}}}-\mu}{\frac{\sigma}{\sqrt{n}}}$

$P=P(z>\frac{42}{\frac{569}{\sqrt{130}}}) + P(z$

$P=P(z>0.8416) + P(z$

Looking at the tables for the standard nominal distribution we get

$P =0.1999+0.1999$

$P =0.3998$

6 0

1 year ago

The cylindrical water tank on a semitrailer has a length of 20 feet. The volume of the tank is equal to the product of pi, the s

Bogdan [553]

Answer:

V = 20πr²

Step-by-step explanation:

In this question, volume of the cylindrical tank has been defined as,

Volume V of the tank = Product of π, the square of the radius of the tank 'r' and the length of the tank 'h'.

Therefore, formula to calculate the formula will be,

V = πr²h

If the length of the cylindrical trailer is,

h = 20 feet

Then the volume of the trailer will be,

V = πr²(20)

V = 20πr²

7 0

2 years ago

Please help me!

wel

12x^3 -6x^2+8x-4
6x^2(2x-1)+4(2x-1)
so ans, (6x^2 +4)(2x-1)

Eric grouped right

8 0

2 years ago

Read 2 more answers

See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se

REY [17]

Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 6, p = 0.2$

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015$

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064$

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564$

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if $P(X \geq 5) < 0.05$

We have that

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05$

Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

5 0

1 year ago

If ce = 7x+4, find the value of x

Kryger [21]

Answer:

x = $\frac{y}{7} - \frac{4}{7}$

Step-by-step explanation:

Since it will be easier, just set "ce" as one term. Let ce = y

You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other.

Do the opposite of PEMDAS.

First, subtract 4 from both sides:

y = 7x + 4

y (-4) = 7x + 4 (-4)

y - 4 = 7x

Next, Divide 7 from both sides:

(y - 4)/7 = (7x)/7

(y - 4)/7 = x

x = (y/7) - (4/7)

Your value of x is $\frac{y}{7} - \frac{4}{7}$

~

4 0

2 years ago

Read 2 more answers