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dybincka [34]
1 year ago
14

Plz answer quickly!!!!!!!

Mathematics
1 answer:
ValentinkaMS [17]1 year ago
6 0

Answer:

<em>(A). x ≥ </em>\frac{16}{5}<em> and x ≤ - </em>\frac{3}{4}<em> </em>

Step-by-step explanation:

5x - 4 ≥ 12 ⇔ 5x ≥ 16 ⇒ <em>x ≥ </em>\frac{16}{5}<em> </em>

<em>and </em>

12x + 5 ≤ - 4 ⇔ 12x ≤ - 9 ⇔ 4x ≤ - 3 ⇒ <em>x ≤ - </em>\frac{3}{4}

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Compute E(X) for the following random variable X : X=Number of tosses until all 10 numbers are seen (including the last toss) by
julsineya [31]

Answer:

For 10 tosses we have that E(X)=10

Therefore E(i)= 1/10 +2/10 +3/10....10/10

This implies that 40/10=E(i)

Therefore E(10) =40/10

= 4.

8 0
1 year ago
The epicenter of an earthquake is the point on Earth’s surface directly above the earthquake’s origin. A seismograph can be used
DaniilM [7]

Answer:

I used desmos and plotted all three circles. The point that hey all intersected was (-1, 3).

Step-by-step explanation:

5 0
2 years ago
Webassign find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (6, 36), an
Dvinal [7]
First find the tangent line

dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36

alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2

so we do \int\limits^6_0 {x^2} \, dx - \int\limits^6_0 {12x-36} \, dx = \int\limits^6_0 {x^2-(12x-36)} \, dx = \int\limits^6_0 {x^2-12x+36} \, dx =
[\frac{x^3}{3}-6x^2+36x]\limits^6_0=(\frac{6^3}{3}-6(6)^2+36(6))-(0)=\frac{216}{3}-216+216= 72+0=72

the area under the curve bounded by the lines and the x axis is 72 square units
4 0
1 year ago
Let’s assume the following statements are true: Historically, 75% of the five-star football recruits in the nation go to univers
marishachu [46]
<span>Given:
75% of the five-star football recruits in the nation go to universities in the three most competitive athletic conferences. </span>→ 25% goes to other schools.
<span>
five-star recruits get full football scholarships 93% of the time, regardless of which conference they go to. </span>→ 7% of the 5-star recruits don't get full football scholarships.<span>

a. The probability that a randomly selected five-star recruit who chooses one of the best three conferences will be offered a full football scholarship? 
75% * 93% = 69.75%

b. What are the odds a randomly selected five-star recruit will not select a university from one of the three best conferences?
25% of selected five-star recruit will not select a university from one of the three best conferences. I got the number based on the given data. Since, 75% will go, the remaining percent won't go. Total percentage should be 100% of the population. 

c. Explain whether these are independent or dependent events. Are they Inclusive or exclusive? 
These are independent events. One can still go to different school and still be legible for the full football scholarship. 

For question 2, pls. see attachment.</span>

4 0
2 years ago
Answer the following question. Click on symbol to choose correct answer. Given: R = {(x, y): y = -x^2} What is the range of R? y
3241004551 [841]

Answer: c

I answered c and got a 100 so it has to be it

3 0
2 years ago
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