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RoseWind [281]
2 years ago
9

The Honor Society held a canned goods drive. They ran great advertising campaigns and collections increased. The following table

represents collections
------------------|--------------------
Day Cans Collected
------------------|---------------------
1 | 15
------------------|---------------------
2 | 20
----------------------------------------
3 | 25
----------------------------------------
4 | 30
----------------------------------------
5 | 35
----------------------------------------
6 | 40



1. The rate of change is?
a)5
b)15
c)25

2. The rate of change represents?
a) The difference in the number of cans from day 1 to day 6
b) The number of days cans collected
c)the number of cans collected per day
Mathematics
2 answers:
OLEGan [10]2 years ago
4 0
#1) The correct answer is A) 5.
#2) The correct answer is C) the number of cans collected per day.

We find the rate of change by finding the change int he outputs, the change in the inputs, and writing it as output/input:

(20-15)/(2-1) = 5/1 = 5

The rate of change tells us how many cans (on average) per day were collected.
hichkok12 [17]2 years ago
4 0

Answer:

#1) The correct answer is A) 5.

#2) The correct answer is C) the number of cans collected per day.

Step-by-step explanation:

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In parallelogram WXYZ, WY = 12 in., XZ = 16 in., WX = 10 in., and XY = 9 in. What is the length of line segment MX? 6 in. 7 in.
nataly862011 [7]

Answer:

Using the charasteristics of a parallelogram, the length of line segment MX is 8 in (Third option).

Step-by-step explanation:

In parallelogram WXYZ:

WY=12 in., this is a diagonal in the parallelogram

XZ=16 in., this is the other diagonal in the parallelogram

WX=10 in., this is one of the sides of the parallelogram

XY=9 in., this is the other side of the parallelogram

MX=? this segment is between the vertex X and the point of intersection of the diagonals

In a parallelogram the diagonals intersect (point M) dividing them in equal parts each other, then:

MX=MZ=XZ/2

MX=MZ=(16 in.)/2

MX=MZ=8 in.

 

8 0
2 years ago
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PLEASE HELP ME!
dezoksy [38]
Thicknesses at different point are: <span>41, 38, 36, 29, 34, 44, 46, 43, 35, 40


In increasing order: 29, 34, 35, 36, 38, 40, 41, 43, 44, 46

Median = (38+40)/2 = 39m</span>

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Three highways connect city A with city B. Two highways connect city B with city C.
QveST [7]
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
0.992\times0.96=0.9523

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:0.9984\times0.96=0.95846

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
0.992\times0.992=0.9841

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
P(A\cup B)=P(A)+P(B)-P(A\cap B)
0.9523+0.8-(0.9523\times0.8)=0.99
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.


4 0
2 years ago
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