All we have to do here is divide 4 by 2
4 ÷ 2 = 2
Therefore, the artist can paint 2 paintings an hour making the unit rate, 2 paintings per hour.
Hope this helps
-AaronWiseIsBae
Answer:
Using the charasteristics of a parallelogram, the length of line segment MX is 8 in (Third option).
Step-by-step explanation:
In parallelogram WXYZ:
WY=12 in., this is a diagonal in the parallelogram
XZ=16 in., this is the other diagonal in the parallelogram
WX=10 in., this is one of the sides of the parallelogram
XY=9 in., this is the other side of the parallelogram
MX=? this segment is between the vertex X and the point of intersection of the diagonals
In a parallelogram the diagonals intersect (point M) dividing them in equal parts each other, then:
MX=MZ=XZ/2
MX=MZ=(16 in.)/2
MX=MZ=8 in.
Thicknesses at different point are: <span>41, 38, 36, 29, 34, 44, 46, 43, 35, 40
In increasing order: 29, 34, 35, 36, 38, 40, 41, 43, 44, 46
Median = (38+40)/2 = 39m</span>
Median thickness is 39m
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.