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ra1l [238]
2 years ago
6

In parallelogram WXYZ, WY = 12 in., XZ = 16 in., WX = 10 in., and XY = 9 in. What is the length of line segment MX? 6 in. 7 in.

8 in. 9 in.
Mathematics
2 answers:
nataly862011 [7]2 years ago
8 0

Answer:

Using the charasteristics of a parallelogram, the length of line segment MX is 8 in (Third option).

Step-by-step explanation:

In parallelogram WXYZ:

WY=12 in., this is a diagonal in the parallelogram

XZ=16 in., this is the other diagonal in the parallelogram

WX=10 in., this is one of the sides of the parallelogram

XY=9 in., this is the other side of the parallelogram

MX=? this segment is between the vertex X and the point of intersection of the diagonals

In a parallelogram the diagonals intersect (point M) dividing them in equal parts each other, then:

MX=MZ=XZ/2

MX=MZ=(16 in.)/2

MX=MZ=8 in.

 

Agata [3.3K]2 years ago
4 0

Answer: 8 in


M is the center created by diagonal lines leading though the parallelogram, taking this into account the correct answer is half of XZ.


16/2 = 8

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Answer:

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Step-by-step explanation:

Data provide in the question:

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Now,

Dividing both numerator and denominator by t, we have

\lim _{t \rightarrow \infty} \frac{\frac{1}{t} 35 t}{\frac{1}{t}(320+t)}=\lim _{t \rightarrow \infty} \frac{35}{\frac{320}{t}+1}=35

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