Answer: 345.02
Step-by-step explanation:
The answer to this question would be:
<span>The function f(x) = 9,000(0.95)x represents the situation.
After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
</span>
In this problem, there are 9,000 bees and the amount is decreased 5% each year. Decreased 5% would be same as become (100%-5%=)95% each year. Then the function should be like:
f(x)= 9,000 * 95%^ x= 9,000 * 0.95^x
If you put X=2 and X=4 the result would be:
<span>f(2) = 9,000* (0.95)^2= 8122.5 (round up to tenth will be 8120)
</span>f(4) = 9,000* (0.95)^4= 7330.5
Answer:
Step-by-step explanation:
P(greater than 10 successes)≈
13/20 =0.65
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
$15
Step-by-step explanation:
Let Frank be f
Deandra be d and
Charlie be c
f = 3d ......(i)
c=$20+f.....(ii)
c=$65........(iii)
Equate (ii) and (iii)
$20+f = $65
f = $45.......(iv)
Equate (i) and (iv)
3d = $45
d = $15
Deandra has $15.