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2 years ago

15

Jenny buys 222222 sports drinks for her soccer team. They are on sale for \$0.35$0.35dollar sign, 0, point, 35 off per drink. Je

nny paid \$18.70$18.70dollar sign, 18, point, 70 for the 222222 sports drinks.
What question does the equation 22(x-0.35)=18.7022(x−0.35)=18.7022, left parenthesis, x, minus, 0, point, 35, right parenthesis, equals, 18, point, 70 help answer?

1 answer:

Pie2 years ago

7 0

Answer:

A. What is the pre-sale price of a sports drink?

Step-by-step explanation:

Hope this helps!

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Nikki used the calculations shown to determine whether a carton of 12 eggs or a carton of 18 eggs was the better buy. A carton o

Lemur [1.5K]

Given :

A carton of 12 eggs or a carton of 18 eggs was the better buy. A carton of 12 eggs cost $2.39, and a carton of 18 eggs cost $3.39. Unit price of the 12-egg carton = ($2.39)(12 eggs) = $28.68 per egg Unit price of the 18-egg carton = ($3.39)(18 eggs) = $61.02 per egg The 12-egg carton has the lower unit cost, so it is the better buy.

To Find :

What was her first error.

Solution :

Her first error is to find Unit price of egg in each carton.

To find, unit price we should divide total amount by number of units :

Unit price for carton of 12 eggs, $ (2.39)/12 = $0.199 .

Hence, this is the required solution.

4 0

2 years ago

Sarah is planning to spend a week at her friend's summer house in Miami Beach. All meals will be provided by her friend's parent

Rus_ich [418]

Answer:

500$

Step-by-step explanation:

5 0

2 years ago

F(x)=3x 2 +9f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 9 and g(x)=\dfrac{1}{3}x^2-9g(x)= 3 1 x 2

34kurt

Answer:

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

$g(f(x)) = 3x^4 + 18x^2 + 18$

<em>f(x) and g(x) and not inverse functions</em>

Step-by-step explanation:

Given

$f(x) = 3x^2 + 9$

$g(x) = \dfrac{1}{3}x^2 - 9$

Required

Determine f(g(x))

Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

$f(x) = 3x^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9$

Expand Brackets

$f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = \frac{1}{3}x^4 - 9x^2 - 9x^2 + 243 + 9$

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

Calculating g(f(x))

$g(x) = \dfrac{1}{3}x^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9$

$g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9$

Expand Brackets

$g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9$

$g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9$

$g(f(x)) = 3x^4 + 18x^2 + 18$

Checking for inverse functions

$f(x) = 3x^2 + 9$

Represent f(x) with y

$y = 3x^2 + 9$

Swap positions of x and y

$x = 3y^2 + 9$

Subtract 9 from both sides

$x - 9 = 3y^2 + 9 - 9$

$x - 9 = 3y^2$

$3y^2 = x - 9$

Divide through by 3

$\frac{3y^2}{3} = \frac{x}{3} - \frac{9}{3}$

$y^2 = \frac{x}{3} - 3$

Take square root of both sides

$\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}$

$y = \sqrt{\frac{x}{3} - 3}$

Represent y with g(x)

$g(x) = \sqrt{\frac{x}{3} - 3}$

Note that the resulting value of g(x) is not the same as $g(x) = \dfrac{1}{3}x^2 - 9$

<em>Hence, f(x) and g(x) and not inverse functions</em>

4 0

2 years ago

Preston is making cookies. He has fraction 4 over 5 cup of flour in a bag. He then used two fraction 1 over 10 cup scoops of flo

Art [367]

I'm pretty sure the answer will be 6/10

Hope this helps, best of luck, terribly sorry if I'm wrong if I am my apologies

~Animaljamissofab ♥

5 0

2 years ago

Read 2 more answers

vegetable ghee is stored in the cylindrical vessel of internal radius 1.4m height 1.5m. if it is transferred into the rectangula

irina1246 [14]

Answer:

<em>5,598 cans are required to empty the vessel</em>

Step-by-step explanation:

The volume of a cylinder of radius r and height h is:

$V = \pi r^2h$

The volume of a box of dimensions X, Y, and Z is:

V=X.Y.Z

A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:

$V_1 = \pi 1.4^2*1.5$

$V_1=9.236\ m^3$

Converting to cubic cm:

$V_1=9.236*1,000,000\ cm^3$

$V_1=9,236,282\ cm^3$

The volume of each rectangular tin can is:

$V_2=33*10*5=1,650\ cm^3$

$V_2=1,650\ cm^3$

The number of cans required to empty the vessel is:

$V_1/V_2=9,236,282/1,650 = 5,598$

5,598 cans are required to empty the vessel

5 0

2 years ago