Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 =
=p
The formula for the standard deviation of a proportion is 
Solving for the standard deviation gives;

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2×
= 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;


Therefore, the z-score more than 2 ×
which is significant.
Answer:
y = 0
Step-by-step explanation:
Given
f(x) = 4x² +x⁵ +10x³ +5x+8x⁴
Required
Determine the y intercept
The y intercept of a function is a point where x = 0
So, we have to substitute 0 for x in the above function
f(x) = 4x² +x⁵ +10x³ +5x+8x⁴ becomes
f(0) = 4(0)² +(0)⁵ +10(0)³ +5(0)+8(0)⁴
f(0) = 4 * 0 + 0 + 10 * 0 + 5 * 0 + 8 * 0
f(0) = 0 + 0 + 0 + 0 + 0
f(0) = 0
Substitute y for f(0)
y = 0
Hence, the y intercept is 0
Let no. of adult tickets be x and senior citizen tickets be y.
x + y = 556
22x + 12y = 8492
Solving by simultanous equations,
x = 182 adult tickets
y = 374 senior citizen tickets
Answer:
correct option is △XYZ ~ △X'Y'Z'.
Step-by-step explanation:
since ΔXYZ is dilated by some scale factor so, the resulting triangle can not be congruent to the ΔXYZ. so option 2 is wrong.
as we have explained that the two triangles are not congruent then it's sides and angles also can't be congruent so, option 3 is also incorrect.
As we don't know by what factor the triangle XYZ is dilated so we can't say anything about correctness of option 4 and 5.
ΔXYZ was reflected over a vertical line and then dilated so the resulting ΔX'Y'Z' is similar to ΔXYZ.
i.e., △XYZ ~ △X'Y'Z'.