Answer: 60%
Step-by-step explanation: 24/40 = .6 x 100 = 60
Answer:
$120.14
Step-by-step explanation:
This question is an example of a compound percentage decrease.
To work this out you would first need to convert the percentage of 25 into a decimal. You can do this by dividing the percentage of 25 by 100, this gives you 0.25. This is because percentages are out of 100.
The next step is to minus 0.25 from 1, this gives you 0.75. This is because we are working out the percentage decrease.
The final step is to multiply the amount of 900 by 0.75 to the power of 7, this gives you $120.14.
1) Divide 25 by 100.
2) Minus 0.25 from 1.
3) Multiply 900 by 0.75 to the power of 7.
Answer: (3,45) and (15,9)
Step-by-step explanation:
LCM x HCF = 45*3 = 135
so, the pairs which has HCF as 3 and LCM as 45 are (3,45) and (15,9)
Hey there! :)
Line passes through (2, -4) & parallel to y = 3x+ 2
Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope. "M" is simply a place mat so if we look at our given line, the "m" value is 3. Therefore, our slope is 3.
We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our slope for our new line will be 3.
Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (2, -4) with a slope of 3.
y-y₁=m(x-x₁)
Let's start by plugging in 3 for m (our slope), 2 for x1 and -4 for y1.
y - (-4) = 3(x - 2)
Simplify.
y + 4 = 3x - 6
Simplify by subtracting 4 from both sides.
y = 3x - 10
~Hope I helped!~
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
