Answer:
The perimeter is
Step-by-step explanation:
we know that
A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal
so
In this problem
PS=QR ----> equation A
SR=PQ ----> equation B
The perimeter of parallelogram PQRS is
P=PQ+QR+SR+PS ----> equation C
substitute equation A and equation B in equation C
we have
substitute in the formula of perimeter
Answer:
Step-by-step explanation:
We have the following expression:
We can find the GCF with the following steps.
1. Find the GCF for the numerical part 15 and -21
The factors for 15 are : 1,3,5,15
The factors for -21 are -21,-7,-3,-1,1,3,7,21
And the common factors are 1,3
The GCF for the numerical part is 3*1 = 3
2. Find the GCF for the variable
The factors of x^2 are : x*x
The factors of x are: x
The common factors are x for this case, so then the GCF for the variable part is x
3. Multiply the two results from steps 1 and 2
GCf= 3*x = 3x
If we consider the new expression:
We can find the GCF with the following steps.
1. Find the GCF for the numerical part 15 and -21
The factors for 15 are : 1,3,5,15
The factors for -21 are 1,3,7,21
And the common factors are 1,3
The GCF for the numerical part is 3*1 = 3
2. Find the GCF for the variable
The factors of x^2 are : x*x
The factors of x are: x
The common factors are x for this case, so then the GCF for the variable part is x
3. Multiply the two results from steps 1 and 2
GCf= 3*x = 3x
And as we can see both GCF are equal. So then we satisfy the condition required.
The resultant velocity of the plane is the sum of the two velocity vectors which are perpendicular to each other. See the attached figure.
The magnitude of the resultant velocity is
.
The approximate value of the actual velocity of the plane is . Correct choice is (D).
