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topjm [15]
2 years ago
11

Which statement is correct? StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFrac

tion less-than-or-equal-to (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline) StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction less-than (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline) StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction greater-than (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline) StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction = (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline)
Mathematics
2 answers:
erma4kov [3.2K]2 years ago
8 0

The answer is C.

I hope this helps :)

stellarik [79]2 years ago
5 0
Mannn what the heck...it’s so confusing sorry I couldn’t read.its messing
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Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 ​ of a blanke
Gnesinka [82]

Answer:


Step-by-step explanation:

Given that Darcie wants to donate minimum 3 blankets to donate to a homeless shelter.  No of days left =60

No of days to complete one blanket = 1/(1/15) = 15 days

Hence in 60 days she has to complete ≥3 blankets

No of days she has to utilize for this will be ≥3(15)=45

No of days she can skip crocheting ≤15

Let x be the no of days crocheted and y no of days skipped

Then x+y≤60

See the graph attached as x axis for days crocheted and y for days skipped

No of blankets can be either 3 or 4.


4 0
2 years ago
Read 2 more answers
In the diagram shown of circle A, tangent MB is drawn along with chords BAC and BF . Secant MFE intersects BAC at G. It is known
mote1985 [20]

Answer:

  • arc BF = 76°
  • ∠M = 31°
  • ∠BGE = 121°
  • ∠MFB = 111°

Step-by-step explanation:

(a) ∠FBM is the complement of ∠FBC, so is ...

  ∠FBM = 90° -52° = 38°

The measure of arc BF is twice this angle, so is ...

  arc BF = 2∠FBM = 2(38°)

  arc BF = 76°

__

(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...

  ∠M = (1/2)(138° -76°) = 62°/2

  ∠M = 31°

__

(c) arc FC is the supplement to arc BF, so has measure ...

  arc FC = 180° -arc BF = 180° -76° = 104°

∠BGE is half the sum of arcs BE and FC, so is ...

  ∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2

  ∠BGE = 121°

__

(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...

  ∠MFB = 180° -∠M -∠FBM = 180° -31° -38°

  ∠MFB = 111°

3 0
2 years ago
Ellie has a delivery van which she is going to deliver boxes each box is a cuboid brain.ly 45cm by 40cm by 35cm the space in the
jek_recluse [69]

Answer:

It will take Ellie 64 minutes to put as many boxes as possible.

Step-by-step explanation:

Let us work with meters.

The dimensions of Ellie's boxes in meters are: 0.45m by 0.40m by 0.35 ( <em>to convert from centimeters to meters we just divide by 100, because 1m =100cm).</em> therefore the volume of each box is:

<em>V_{box}=0.45m*0.40m*0.35m=0.063m^3</em>

Now the dimensions of the empty van are 3.6m by 1.6m by 2.1 m, therefore its volume V_{van} is:

V_{van}=3.6m*1.6m*2.1m=12.096m^3.

So the amount of boxes that Ellie can put in the van is equal to the volume of the van V_{van} divided by the volume V_{box} of each box:

\frac{V_{van}}{V_{box}} =\frac{12.096}{0.063}=\boxed{192\:boxes }

So 192 boxes can be put into the van.

Now Ellie can put 3 boxes in the van in 1 minute, therefore the amount of time it will take her to put 192 boxes into the van will be:

\frac{192boxes}{3boxes/minute} =\boxed{64\:minutes}

So it takes Ellie 64 minutes to put as many boxes into the van as she can.

4 0
2 years ago
I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°)
galina1969 [7]
Get rid of cos2x by dividing both the values. So Sin2x/cos2x +3cos2x/cos2x.
Tan2x = 3
2x = -71.5 so x is -35.6
Use the quadrant method and add 360 twho the two values tou get.
7 0
2 years ago
If you apply the changes below to the quadratic parent function, f(x) = x2, what is the equation of the new function? Shift 3 un
Alex17521 [72]
To apply the changes to the equation of a vertical stretch of 4 and a translation of 3 units to the right, as well as the correct answer would be choice B.

The reason for this is when you apply a vertical stretch, because it changes the y-values (which causes it to vertically stretch or appear skinnier when graphed), you would multiply 4 to f(x) which would look like 4x^2.

Then, since you have a reflection over the x-axis, you must multiply a -1 to f(x) to reflect it over the x-axis which would result in -4x^2.

Finally, it also asks to shift the graph right 3 which by moving it right, you change the x values meaning you will perform f(x-3) to achieve this (subtract the value from x when you move right, and add the value to x when you move left).

This therefore results in your answer, the new graph would be
g(x)= -4(x-3)^2 or choice B.
8 0
2 years ago
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