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MArishka [77]
1 year ago
15

On any night, there is a 92% chance that an burglary attempt will trigger the alarm, and a 1% chance of a false alarm, namely th

at the alarm will go off when there is no burglary. The chance that a house will be burglarized on a given night is 1/1000 . What is the chance of a burglary attempt if you wake up at night to the sound of your alarm?
Mathematics
1 answer:
Semmy [17]1 year ago
3 0

Answer:

Step-by-step explanation:

Step1: P(Burglary) = .001

Step2: P(Alarm|Burglary Happens) = .92

Step3: Probability of alarm going (in total) = P(Alarm) when burglary happens + P(Alarm) when burglary does not happen.

Step4: Use Bayes theorem.

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Read 2 more answers
Alicia sews costumesfor a school play.She takes an average of 86 minutes to sew each costume.How long would she take to sew 16 o
Goryan [66]

Answer:

1376 minutes

Step-by-step explanation:

Alicia sews costumes for schools

She takes 86 minutes to sew one costume

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86 mins= 1 costume

x= 16 costume

Cross multiply

x= 86×16

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3 0
1 year ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
2 years ago
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