Answer:
155 Units
Step-by-step explanation:
Rate of Bug (given) = 11 units PER MINUTE
It never changed direction, so it was going in positive direction (assume).
In 7:15 pm (evening), it was at Point 100,
We want the point at which it was at 7:20 pm.
7:20pm - 7:15pm = 5 minutes
So, time passed 5 minutes. It's rate is 11 units PER MINUTE, so in 5 mins:
11 * 5 = 55 units
<em>Assuming he is going in positive direction</em>, the bug will be at:
100 + 55 = <u>155 Units</u>
Answer:2 2/3 miles per hour
Step-by-step explanation:to get one mile you multiply 1/4 by 4 and to keep 1/4 and 2/3 proportional you also have to multiply 2/3 by 4
Answer:
Step-by-step explanation:
Given that a group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below.
Data set is as ollows:
70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

H0: mu = 60 sec
Ha: mu not equals 60 sec
Mean diff = 2.27

Test statistic = 2.27/SE =0.4815
p value =0.6376
Since p>0.05, we accept null hypothesis
i.e. there is statistical evidence to say that students are reasonably good at estimating one minute
B = base length
a = length of the other two equal sides
The value of 'a' is larger than the value of b. This is because the base is shorter than the other two equal sides. We're told that "one of the longer sides is 6.3 cm", meaning that a = 6.3
Replace every copy of 'a' in the given equation with 6.3; isolate b
2*a + b = 15.7
2*6.3 + b = 15.7
12.6 + b = 15.7
12.6 + b - 12.6 = 15.7 - 12.6 ... see note below
b = 3.1
note: I subtracted 12.6 from both sides. This is using the subtraction property of equality.
Answer:
y = 16x/65
Step-by-step explanation:
Given:
Triangle ABE is similar to triangle ACD. AED and ABC are straight lines
EB and DC are parallel
The area of quadrilateral BCDE = xcm²
The area of triangle ABE = ycm²
Find attached the diagram from the above information.
In similar triangles, the ratio of their corresponding angles are equal.
Also, the ratio of the area of the two triangles = square of ratio of the corresponding sides of the two triangles.
Area ∆ACD/area of ∆ABE = (DC/EB)²
Area ∆ACD/area of ∆ABE = [(area of quadrilateral BCDE +
area of ∆ABE)]/(area of ∆ABE)
(x+y)/y = (DC/EB)²
(x+y)/y = (9/4)²
x+y = (81/16)y
x = (81/16)y - y
x = (81y - 16y)/16
x = 65y/16
Making y subject of formula
16x = 65y
y = 16x/65
An expression for y in terms of x:
y = 16x/65