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Virty [35]
2 years ago
13

The price of salmon at a Fish market is $5.40 per pound this is 150 percent of its price at the supermarket how much would it co

st per pound at the supermarket
Mathematics
2 answers:
REY [17]2 years ago
8 0
Fish market = $5.4
supermarket = 150% of $5.4
150% - - > 1.5
so the cost at the supermarket is 1.5*5.4=8.1.
NikAS [45]2 years ago
3 0

Answer:

B. $3.60

Step-by-step explanation:

Fish market cost = $5.40

supermarket cost = 150% or 1.5

$5.40 / 1.5 = $3.60 ( cost per pound )

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A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 pm it was at
Minchanka [31]

Answer:

155 Units

Step-by-step explanation:

Rate of Bug (given) = 11 units PER MINUTE

It never changed direction, so it was going in positive direction (assume).

In 7:15 pm (evening), it was at Point 100,

We want the point at which it was at 7:20 pm.

7:20pm - 7:15pm = 5 minutes

So, time passed 5 minutes. It's rate is 11 units PER MINUTE, so in 5 mins:

11 * 5 = 55 units

<em>Assuming he is going in positive direction</em>, the bug will be at:

100 + 55 = <u>155 Units</u>

8 0
2 years ago
Read 2 more answers
Hadley paddled a canoe 2/3 mile in 1/4 hour. How fast did Hadley paddle in miles per hour ?
Vitek1552 [10]

Answer:2 2/3 miles per hour

Step-by-step explanation:to get one mile you multiply 1/4 by 4 and to keep 1/4 and 2/3 proportional you also have to multiply 2/3 by 4

5 0
2 years ago
A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
Anit [1.1K]

Answer:

Step-by-step explanation:

Given that a group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are listed below.

Data set is as ollows:

70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714

H0: mu = 60 sec

Ha: mu not equals 60 sec

Mean diff = 2.27

Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714

Test statistic = 2.27/SE =0.4815

p value =0.6376

Since p>0.05, we accept null hypothesis

i.e. there is statistical evidence to say that students are reasonably good at estimating one​ minute

8 0
2 years ago
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the t
Ipatiy [6.2K]
B = base length
a = length of the other two equal sides

The value of 'a' is larger than the value of b. This is because the base is shorter than the other two equal sides. We're told that "one of the longer sides is 6.3 cm", meaning that a = 6.3

Replace every copy of 'a' in the given equation with 6.3; isolate b
2*a + b = 15.7
2*6.3 + b = 15.7
12.6 + b = 15.7
12.6 + b - 12.6 = 15.7 - 12.6 ... see note below
b = 3.1

note: I subtracted 12.6 from both sides. This is using the subtraction property of equality. 
7 0
2 years ago
Triangle ABE is similar to triangle ACD. AED and ABC are straight lines. EB and DC are parallel. AE = 5 cm, BC = 4.5 cm, BE = 4
lianna [129]

Answer:

y = 16x/65

Step-by-step explanation:

Given:

Triangle ABE is similar to triangle ACD. AED and ABC are straight lines

EB and DC are parallel

The area of quadrilateral BCDE = xcm²

The area of triangle ABE = ycm²

Find attached the diagram from the above information.

In similar triangles, the ratio of their corresponding angles are equal.

Also, the ratio of the area of the two triangles = square of ratio of the corresponding sides of the two triangles.

Area ∆ACD/area of ∆ABE = (DC/EB)²

Area ∆ACD/area of ∆ABE = [(area of quadrilateral BCDE +

area of ∆ABE)]/(area of ∆ABE)

(x+y)/y = (DC/EB)²

(x+y)/y = (9/4)²

x+y = (81/16)y

x = (81/16)y - y

x = (81y - 16y)/16

x = 65y/16

Making y subject of formula

16x = 65y

y = 16x/65

An expression for y in terms of x:

y = 16x/65

3 0
2 years ago
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