If the parent function is y = 3x, which is the function of the graph? y = 0.5(3)x y = 2(3)x y = −2(3)x y = −0.5(3)x

Type the correct answer in each box. Spell all the words correctly, and use numerals instead of words for numbers. If necessary,

Morgarella [4.7K]

Answer:

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of (x-2, y) unit(s) and a across the x-axis.

Step-by-step explanation:

The triangle ABC is shown in the image attached. The coordinates of the triangle are A(8, 8), B(10, 4), C(2, 6), while the triangle A'B'C' is at A'(6, -8), B'(8, -4), C'(0, -6).

A transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, dilation and rotation.

If a point O(x, y) is translated a units on the x axis and b units on the y axis, the new coordinate is O'(x+a, y+b).

If a point O(x, y) is reflected across the x axis, the new coordinate is O'(x, -y)

Hence if triangle ABC is translated -2 units on the x axis (2 units left), the new coordinates are A*(6, 8), B*(8, 4), C*(0, 6). If a reflection across the x axis is then done, the new coordinates are A'(6, -8), B'(8, -4), C'(0, -6).

7 0

2 years ago

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Every weekday, Mr. Jones bikes from his home to his job. Sometimes he rides along two roads, the long route that is shown by the

notka56 [123]

Answer:

(A)6 kilometers

Step-by-step explanation:

First, we determine the value of a using Pythagoras Theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\17^2=a^2+15^2\\a^2=17^2-15^2\\a^2=289-225\\a^2=64\\a^2=8^2\\a=8$ km$

Therefore:

Distance along the long route = 8 + 15 =23 km

Distance along the shortcut =17 km

Difference =23-17 =6km

Therefore, Mr. Jones bikes 6km less when he takes the shortcut instead of the long route.

5 0

2 years ago

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The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds after being dropped. The b

mel-nik [20]

Answer:

Third option: 5.48

Step-by-step explanation:

Given the quadratic model that represents the approximate height in meters of the ball $f(x)=-5x^2 +200$ . the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting $f(x)=50$ and solving for x.