2 years ago

If h=7 and i=3 find the value of 2h + 2i

Mathematics

2 answers:

Elza [17]2 years ago

7 0

2(h) + 2(i)
2(7) + 2(3)
14 + 6 = 20

padilas [110]2 years ago

5 0

20 is the answer hope this helps

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If x and y are two positive real numbers such that x 2 +4y 2 =17 and xy =2, then find the value of x- 2y. a. 3 b. 4 c. 8 d. 9

Dafna11 [192]

Answer: The value of x- 2y is a. $\pm 3$ .

Step-by-step explanation:

Given: x and y are two positive real numbers such that $x^2+4y^2=17$ and $xy= 2$ .

Consider $(x-2y)^2=x^2-2(x)(2y)+(2y)^2\ \ \ [(a+b)^2=(a^2-2ab+b^2)]$

$=x^2-4xy+4y^2$

$=x^2+4y^2-4(xy)$

Put $x^2+4y^2=17$ and $xy= 2$ , we get

$(x-2y)^2=17-4(2)=17-8=9$

$\Rightarrow\ (x-2y)^2=9$

Taking square root on both sides , we get'

$x-2y= \pm3$

Hence, the value of x- 2y is a. $\pm 3$ .

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1 year ago

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qaws [65]

15x^2y^4z^2 will be your answer please thank me and friend me

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1 year ago

Which statement about the ordered pairs (3, −8) and (4, 4) is true for the equation 3x−y4=113x−y4=11 ? a.(3, −8) is a solution t

adelina 88 [10]

3x - 4y = 11

For (3, -8): 3(3) - 4(-8) = 9 + 32 = 41 ≠ 11.

For (4, 4): 3(4) - 4(4) = 12 - 16 = -4 ≠ 11

<span>Neither ordered pair is a solution.</span>

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