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2 years ago

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A boxplot of weights (in grams) for 578 chicks is given. The right hand axis marks the five number summary. Use this plot to dec

ide if the following statement is true or false. A chick weighing 300 grams is an outlier. [Note: use the Upper Fence criterion].a) trueb) false

1 answer:

podryga [215]2 years ago

7 0

Answer:

the anwser is in the text

Step-by-step explanation:

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Two commuters leave the same city at the same time but travel in opposite directions. One car is traveling at an average speed o

r-ruslan [8.4K]

Answer:

5 hours

Step-by-step explanation:

The formula to relate speed, distance and time is:

D = V * t

Where D is the distance, V is the speed and t is the time.

As they are in opposite directions, we need to sum the speed.

So the total speed is:

V = 63 + 59 = 122 mph

So using this value and V and using D = 610, we have:

610 = 122 * t

t = 610 / 122 = 5 hours

So they will be 610 miles apart after 5 hours.

3 0

2 years ago

Bernie helped design a magician costume for a school play. He used 5.75 feet of ribbon for the magician's wand. He used 11.75 fe

Nonamiya [84]

Answer:

The ribbon cost per foot $0.6 per foot

Step-by-step explanation:

Total number of ribbon used = (5.75 + 11.75) = 17.50 feet

17.50 feet of ribbon cost = $10.50

1 foot of ribbon cost = x

Cross Multiply

17.50 × x = 1 foot × $10.50

x = 1 foot × 10.50/17.50

x = $0.6

The ribbon cost per foot $0.6 per foot

8 0

2 years ago

Read 2 more answers

The linear function m=55-8.5b represents the amount m (in dollars) of money that you have after buying b books. Find the domain

Amiraneli [1.4K]

Answer:

The domain is (-∞ , ∞)

The domain is continuous

Step-by-step explanation:

Here, we want to identify the domain of the linear function

The domain in this case can be represented by the set of all real numbers.

When we talk of the domain of a function, we are simply referring to the the range of values between the smallest value on the x-axis and the largest number on the x-axis

Hence, mathematically, we are simply considering the smallest value of b up to the largest value of b in this case. Where b simply represents the number of books

Thus, the domain here will be (-∞ , ∞)

On if the domain is discrete or continuous, we can see that the domain is continuous.

The domain is continuous simply because, the domain we have contains all the values and not some in the set of real numbers. If it had contain only some, then it would have been discrete. But since it contains all, it is continuous

8 0

2 years ago

During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str

Brilliant_brown [7]

Answer:

number of successes

$k = 235$

number of failure

$y = 265$

The criteria are met

A

The sample proportion is $\r p = 0.47$

B

$E =4.4 \%$

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from the true population proportion will not more than 4.4%

Ci

$r = 0.514 = 51.4 \%$

$v = 0.426 = 42.6 \%$

D

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

E

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

Yes our result would support the claim because

$\frac{1}{3 } \ of N < \frac{1}{2} (50\%) \ of \ N , \ Where\ N \ is \ the \ population\ size$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 500$

The sample proportion is $\r p = 0.47$

Generally the number of successes is mathematical represented as

$k = n * \r p$

substituting values

$k = 500 * 0.47$

$k = 235$

Generally the number of failure is mathematical represented as

$y = n * (1 -\r p )$

substituting values

$y = 500 * (1 - 0.47 )$

$y = 265$

for approximate normality for a confidence interval criteria to be satisfied

$np > 5 \ and \ n(1- p ) \ >5$

Given that the above is true for this survey then we can say that the criteria are met

Given that the confidence level is 95% then the level of confidence is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p (1- \r p}{n} }$

substituting values

$E = 1.96 * \sqrt{ \frac{0.47 (1- 0.47}{500} }$

$E = 0.044$

=> $E =4.4 \%$

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

substituting values

$0.47 - 0.044 < p < 0.47 + 0.044$

$0.426 < p < 0.514$

The upper limit of the 95% confidence interval is $r = 0.514 = 51.4 \%$

The lower limit of the 95% confidence interval is $v = 0.426 = 42.6 \%$

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

$\frac{1}{3 } < \frac{1}{2} (50\%)$

3 0

2 years ago

Marissa buys a licorice candy rope to share with some friends. The rope is 30 and two thirds inches long. She begins to cut the

adell [148]

9!
3.33 x 9 =(about)= 29.97

4 0

2 years ago