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patriot [66]
1 year ago
11

Alannah has two lengths of ribbon.

Mathematics
1 answer:
ankoles [38]1 year ago
7 0

Answer:

Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.

Step-by-step explanation:

Alannah has two ribbons one length is 36cm and other is 45cm.

It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.

So, let's find greatest common factor for both 36 and 45.

Let's prime factor each number

36= 2*2*3*3

45= 3*3*5

So, GCF is product of common factors for both numbers.

GCF= 3*3 =9

So, longest possible length for each of the shorter lengths of ribbon is 9 cm.

Learn more about GCF in brainly.com/question/21612147.

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Greatest common factor of 88 and 48
kupik [55]
GFC is 8. Use a tree of 88 and 48. 88= 2^3 x 11 or 2 x 2 x 2 x 11

48=2^4 x 3 or 2 x 2 x 2 x 2 x 3 see how many groups count as the number once and multiply and bam GFC. Hope I helped! (:
4 0
2 years ago
The size of fish is very important to commercial fishing. A study conducted in 2012 found the length of Atlantic cod caught in n
devlian [24]

Answer:

The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have that:

A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 49.9 cm and a standard deviation of 3.74 cm, so \mu = 49.9, \sigma = 3.74.

What is the length in cm of the longest 15% of Atlantic cod in this area?

We have to find the value of X for the value of Z that has a pvalue of 0.85.

Looking at the zscore table, we have that Z = 1.04 has a pvalue of 0.8508. So, we have to find the value of X when Z = 1.04, \mu = 49.9, \sigma = 3.74.

So

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 49.9}{3.74}

X - 49.9 = 3.8896

X = 53.7896

The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.

8 0
2 years ago
Lorie is using long division to find the quotient of x^3 + 6x^2 + 5 and x^2 + x -1, as shown at the bottom of this question.
meriva

Answer:

Option (B)

Step-by-step explanation:

x² + x - 1) x³ + 6x² + 0x + 5 ( x + 5

           - (<u>x³ +   x²  -  x</u>)

                      5x² + x + 5

                    -(<u>5x² + 5x - 5)</u>

                             -4x + 10

Result : x+5+\frac{-4x+10}{(x^{2}+x-1)}

By the comparing the result with the Lorie's solution,

She made a mistake in the last step in which she combined the constant incorrectly.

Therefore, Option (B) will be the answer.

7 0
2 years ago
Jerry and Katja are running in a race. Jerry runs really fast for a while. Then, he stops to catch his breath. After he has rest
Elena L [17]
The slope of the lines represent the runners' speeds. Therefore, the purple line represents Jerry, since he started off faster but also stopped in the middle, and the slope became 0 (horizontal portion of the line.)
The red one represents Katja because she started and ended at a constant pace, which is visible in the red line's constant slope.
4 0
2 years ago
Read 2 more answers
John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S
Andreyy89

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work =20\ km/hr

Sheri's commute to work  =500\ m/min

1.61\ km = 1\ mile

John's commute to work in miles per hour = \frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr

Sheri's commute to work in miles per hour =\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr

We can see that Sheri has a faster commute.

Difference between the rates =18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr

∴ Sheri has the faster commute by 6.2 miles/hr.

3 0
2 years ago
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