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Lerok [7]
1 year ago
6

Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the

top of the dam to be 26º. Scarlett's height is 1.65 meters, so the height of the dam is meters. NextReset

Mathematics
2 answers:
Leya [2.2K]1 year ago
8 0
The height of a dam:
h = x + 1.65 m,
where:
x = 90 m · tan 26°
x = 90 · 0.4877
x = 43.90
h = 43.90 m + 1.65 m = 45.55 m
Answer: 
The height of the dam is 45.5 m.
Alla [95]1 year ago
4 0

Answer:

The height of dam =45.5 m.

Step-by-step explanation:

We are given that Scarlett stands 90 m away from the dam and records the angle of elevation to the top of the dam to be 26^{\circ}p

Scarelett's height is 1.65 meters.

We have to find the height of the dam.

Let h be the height of dam

AC=AB+BC

BC=x

h=1.65+x

CD=EB=90 m

In triangle ABE

\theta=26^{\circ}

tan\theta=\frac{perpendicular\;side}{Base}

tan26^{\circ}=\frac{AB}{90}

0.4877=\frac{x}{90}

x=0.4877\times 90

x=43.893 m

Therefore, the height of dam=1.65+43.893=45.543 m

Answer: The height of dam =45.5 m

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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is \mu*n and the standard deviation is s = \sqrt{n}*\sigma

In this question:

n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 6328125}{11250}

X - 6328125 = 1.28*11250

X = 6342525

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0
1 year ago
Nathan flew 3,547 miles from Canada to California during the first part of his trip. He flew 2,567 miles from California to Hawa
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Difference in the number of miles Nathan flew between the first and second parts of his trip is 980 miles

<em><u>Solution:</u></em>

Given that Nathan flew 3,547 miles from Canada to California during the first part of his trip

He flew 2,567 miles from California to Hawaii during the second part of his trip

Therefore,

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second part of his trip = 2567 miles

Difference in the number of miles Nathan flew between the first and second parts of his trip is given as:

difference = first part of his trip - second part of his trip

difference = 3547 - 2567 = 980

Therefore, the difference in number is 980 miles

4 0
2 years ago
Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif
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Answer:

sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

Step-by-step explanation:

given is the Differential equation in I order linear as

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Take Laplace on both sides

L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}

Now if we take inverse we get y(t) the solution

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8 0
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Arte-miy333 [17]

Answer:

f(x) = Three-halves (three-halves) Superscript x

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Since, a function in the form of f(x) = ab^x

Where, a and b are any constant,

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Since, In

f(x) =\frac{2}{3}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

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\frac{3}{2} > 1

Thus, it is a growth function.

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\frac{3}{2} > 1

Thus, it is a growth function.

5 0
2 years ago
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Burka [1]
Tara was right terrence was close but he put the(.) in the wrong spot the correct answer is 243.984 but terrence put 2439.84
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