Given:
Three numbers in an AP, all positive.
Sum is 21.
Sum of squares is 155.
Common difference is positive.
We do not know what x and y stand for. Will just solve for the three numbers in the AP.
Let m=middle number, then since sum=21, m=21/3=7
Let d=common difference.
Sum of squares
(7-d)^2+7^2+(7+d)^2=155
Expand left-hand side
3*7^2-2d^2=155
d^2=(155-147)/2=4
d=+2 or -2
=+2 (common difference is positive)
Therefore the three numbers of the AP are
{7-2,7,7+2}, or
{5,7,9}
When the ball will hit the ground, the height will be zero. So we need to replace

with 0 in our equation, and solve for

:


To solve this equation we are going to use the quadratic formula:

.
From our height equation, we can infer that

,

, and

. So lets replace those values in our quadratic formula to find



or


or

Since time cannot be negative,

is the solution of our equation.
We can conclude that the ball will hit the ground after
2.71 seconds.
S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3
S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24
Answer:
The conclusion that both groups of overweight and non - overweight got cardiovascular benefit from playing DDR games requires Inferential statistics.
Step-by-step explanation:
Inferential statistics is simply a type of research statistic whereby a generalized conclusion is made about a larger group based on representative observations
Now,in the given question, we see that both group hearts were above the minimum recommended for cardiovascular exercise. Now we can infer that the DDR games played by both groups gave them cardiovascular benefits. This conclusion is an example of Inferential statistics where we generalize about a large population based on observations from a small sample.
Thus the conclusion that both groups of overweight and non-overweight got cardiovascular benefit from playing DDR games requires Inferential statistics.
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
The equation of the line in point slope form is

we're going to analyze two cases
<em>First case</em>


substitute

therefore
y plus 6 equals StartFraction 2 Over 5 EndFraction left-parenthesis x plus 2 right parenthesis
<em>Second case</em>


substitute

therefore
y plus 6 equals StartFraction 5 Over 2 EndFraction left-parenthesis x plus 2 right parenthesis