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ad-work [718]
2 years ago
7

Which number produces a rational number when multiplied by 0.5

Mathematics
2 answers:
ivanzaharov [21]2 years ago
5 0
10 is your answer because it is a terminating or repeating decimals
HACTEHA [7]2 years ago
3 0

Answer:

Every Rational number when multiply by 0.5 produces a rational number.

Step-by-step explanation:

Rational Number is a number that can be changed in the formation of \frac{p}{q}, where p & q are real numbers and q ≠ 0.

Even a natural number can also be a rational number since it can be change into \frac{number}{1}

So, the every rational number when multiply by 0.5 produces a rational number. For example: 2 × 0.5 = 1 (rational number)

7 × 0.5 = 3.5 (rational number)

42.63 × 0.5 = 21.315 (rational number)

But, \sqrt{2}\times0.5 = irrational as it has non terminating decimal number (also \sqrt{2} is irrational number)

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The density of gold is 19.3 g/cm3. A weight of 1 ounce is equivalent to a mass of about 28.35 g. Which of these is closest to th
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Answer: The side length of the cube is 2.27cm

Step-by-step explanation:

The options are not given, then let's solve this in a general way.

We know that the density of gold is 19.3g/cm^3.

We also know that 1 oz = 28.35g.

And we know the relation:

Density = mass/volume.

Now, let's find the volume of 8 ounces of gold.

First, let's rewrite the density changing the units, from grams to ounces.

We know that:

1 oz = 28.35g

(1 oz/28.35g) = 1.

Then if we multiply the density by this ( that is equal to 1) we can change the units and leave the actual quantity invariant.

d =  19.3g/cm^3 =  19.3g/cm^3*(1 oz/28.35g) = 0.68 oz/cm^3

Now let's use the equation for the density, knowing this time that the mass is 8 ounces.

0.68 oz/cm^3 = mass/volume = 8oz/V

Let's find the value of V

0.68 oz/cm^3 = 8oz/V

V = 8oz/0.68 oz/cm^3 = 11.76 cm^3

Now, we know that this is a cube.

Remember that the volume of a cube of side length L is:

V = L^3

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L^3 = 11.76 cm^3

L = ∛11.76 cm^3 = 2.27 cm

The side length of the cube is 2.27cm

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1 year ago
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